Answer:- 14.0 moles of hydrogen present in 2.00 moles of .
Solution:- We have been given with 2.00 moles of and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
Mass of Oxygen : 8.0 g
<h3>Further explanation</h3>
Given
1.51 x 10²³ molecules of Oxygen(O₂)
Required
Mass of Oxygen
Solution
1 mol = 6.02 x 10²³ particles(molecules, atoms, ions)
Can be formulated :
N = n x No
n = moles
No = Avogadro's number
Find moles of Oxygen :
n = N/No
n = 1.51 x 10²³ / 6.02 x 10²³
n = 0.251
Mass of Oxygen :
mass = mol x MW O₂
mass = 0.251 x 32 g/mol
mass = 8.032≈ 8.0 g
Answer:
Explanation:
The first thing we calculate are the moles: (50.0 g)/(20.0063 g/mol) =2.5 moles
Then we use the inverse formula for the molarity: (2.5 mol)/(12.0 M) = 0.208 L
My bad, I pressed the wrong button for answer!
Explanation:
At each reflecting surface (benzene and glass) there will be 180 degree phase change.
Now, for constructive interference the optical path in benzene is .
Formula to calculate thickness of a benzene thin film is as follows.
Optical path length through benzene () =
Hence, substituting the given values into the above formula as follows.
Optical path length through benzene =
d =
=
= (as 1 nm =
= 204.9 m
Thus, we can conclude that minimum thickness of benzene is 204.9 m.
Answer:
oxygen is one and sugar as well
Explanation:
carbon dioxide and water gives glucose and oxygen