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3 years ago

Which of the following is the conjugate base of phosphoric acid? *

Chemistry

1 answer:

Crazy boy [7]3 years ago

8 0

Answer:

H2PO4 is the conjugate base of phosphoric acid.

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ANSWER ASAP

Aleksandr-060686 [28]

Answer:

4 orbits in the fourth period.

19 electrons in the atom from group 1 and fourth period.

Explanation:

Potassium has 19 electrons distributed in its 4 orbits

5 0

2 years ago

Given the following balanced reaction between nitrogen gas and oxygen gas to produce nitrous oxide gas, how many moles of nitrou

den301095 [7]

Answer is: 3,3 mol of <span>nitrous oxide gas is produced in this chemical reaction.
</span>Chemical reaction: N₂ + O₂ → 2NO.
n(N₂) = 1,65 mol.
n(NO) = ?
from reaction n(N₂) : n(NO) = 1 : 2.
1,65 mol : n(NO) = 1 : 2.
n(NO) = 3,3 mol.
n - amount of substance.

4 0

3 years ago

Which of the above electron dot diagrams is wrong and why?

Elodia [21]

Answer:

Oxygen, it's supposed to have six valenge electrons.

Explanation:

Count the dots on the oxygen atom, you'll see seven, but there's supposed to be six.

5 0

3 years ago

Read 2 more answers

Gravity is best described as the attractive force___

Delvig [45]

Gravity is nest described as the attractive force that acts between any two objects on earth

Explanation:-

Gravity was found by Sir Eizak Newton
It has formula given by

$\\ \rm\Rrightarrow F=G\dfrac{Mm}{r^2}$

8 0

3 years ago

Read 2 more answers

Last question<br> help<br> im confusion

Andrej [43]

Remark

The given thing on the right is a positron. The mass for these subatomic particles is considered to be 0. It's atomic number is 1 which means it is a blood relative of a proton.

So essentially what happens is that X is one space to the left on the periodic table. But let's solve this a little bit more formally.

Solution

$_{65}^{147}\text{Tb}\longrightarrow _{z}^{y}\text{x} +_{1}^{0}{e}$

y stays the same at 147. It is z that changes.

65 = z + 1 Subtract 1 from both sides.

64 = z

So the chemical with 64 as its position on the periodic table is

Gadolinium and the answer is C

5 0

3 years ago