Basically, this problem asks you to convert units of volume from cm³ to μL. Cubic centimeters is the cubic volume equivalent of milliliters or mL. According to the metric system for L, microliter is 10⁻⁶ of a liter, while milliliter is 10⁻³ of a liter. Therefore, the solution is written as
(1.12×10⁻²³ cm³)*(1 mL/1 cm³)*(10⁻³ L/ 1 mL)*(1μL/10⁻⁶ L) = 1.12×10⁻²⁰ μL
Answer:
A. the reaction rates can change
Explanation:
It can change depending on the the factor and affect
Answer:
The value of the equilibrium constant Kc is 5.45
Explanation:
The "Law of Mass Action" states:
"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."
This constant was called the equilibrium constant. For a reaction:
aA + bB ⇄ cC + dD
the equilibrium constant Kc is:
![Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
In this case, the balanced reaction is:
2 H₂S → 2 H₂ + S₂
So, the equilibrium constant Kc is:
![Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_%7B2%7D%20%5D%5E%7B2%7D%20%2A%5BS_%7B2%7D%20%5D%20%7D%7B%5BH_%7B2%7D%20S%5D%5E%7B2%7D%20%20%7D)
The equilibrium concentrations are
- [H₂S] =0.25 M
- [H₂]= 0.88 M
- [S₂]= 0.44M
Replacing in the definition of equilibrium constant:
Solving:
Kc= 5.45
<u><em>The value of the equilibrium constant Kc is 5.45</em></u>
<u><em></em></u>
Answer:
"Your Choice: Liberation From Your Own Choices or Continue the Choice That Decreases Your Liberation."
Explanation:
Liberation is the freeing or release from something restraining you. In this case, smoking holds you back from doing the things you used to do.
It's not that creative, but I hope this is good enough for you! :D (don't smoke)
Answer:
Explanation:
Fe⁺²(aq) + ClO₂(aq) → Fe⁺³(aq) + ClO₂⁻(aq)
Here oxidation number of Fe is increased from +2 to +3 , so Fe is oxidised .
The oxidation number of Cl is reduced from + 4 to +3 so Cl is reduced .
So ClO₂(aq) is oxidising agent and Fe⁺²(aq) is reducing agent .
