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3 years ago

D = rt, for r Someone please help me out?

Mathematics

1 answer:

lianna [129]3 years ago

4 0

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

All you have to do is divide the t on both sides and you'll get...

$r=\frac{d}{t}$

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Can somebody help me make a word problem of a inequality equation pls

CaHeK987 [17]

Answer:

sure (can i have brainliest?)

Step-by-step explanation:

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3 years ago

What is the reciprical and product of the fraction 3/7?

pychu [463]

Answer:

7/3

Step-by-step explanation:

as it is a reciprocal you must flip the fraction so you can get your answer i hope this helped C:

6 0

2 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago

Please answer this, I need help

frutty [35]

Answer:

-$7

Step-by-step explanation:

20 - 15 = 5

5 + 5 = 10

10 - 10 = 0

0 - 7 = -7

8 0

3 years ago

Read 2 more answers

I need helpppppppp!!!

yarga [219]

Answer: i would say probably 3 or -3

I hope it helps

3 0

3 years ago