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Elan Coil [88]
3 years ago
14

Giving that ai +bj 5i-2j are perpendicular find the value of a if b=3​

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0

Answer:

a = \frac{6}{5}

Step-by-step explanation:

Given

ai + bj and 5i - 2j are perpendicular and b = 3, that is

ai + 3j and 5i - 2j are perpendicular, then

The scalar product = 0 , that is

5a - 6 = 0 ( add 6 to both sides )

5a = 6 ( divide both sides by 5 )

a = \frac{6}{5}

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Step-by-step explanation:

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2 years ago
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nataly862011 [7]

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3 0
3 years ago
Can someone help me asap
stealth61 [152]

Answer:

Option Y is correct.

Step-by-step explanation:

We are given the table representing the relation between new students and returning students for difference classes.

It is required to form the relative frequency table for the given situation.

So, relative frequency table is obtained by dividing the valued by the total number of values in the data set.

<em>Thus, we will get the relative frequency table by dividing the given table values by 500.</em>

Hence, we will get the following table,

                          New Students               Returning Students           Total

10th                         0.01                                   0.34                             0.35

11th                          0.006                                0.324                           0.33

12th                         0.004                                0.316                            0.32

Total                        0.02                                  0.98                                1

Thus, option Y is correct.

4 0
3 years ago
What is the value of x in the equation below?<br> 12 – 2(x-1)=6
JulijaS [17]
X=25 in this equation. But if u divide by 12 it’s -25
5 0
3 years ago
Read 2 more answers
URGENT URGENT helppps plz
Murljashka [212]

Answer:

1) Bigger sector = 168.8pi

1) Smaller sector = 56.3pi

2) Bigger sector = 529.9

3) Smaller sector = 176.6

Step-by-step explanation:

1) Bigger sector =  \frac{270}{360}×pi×15×15

                          = 168.75pi

1) Smaller sector = \frac{360-270}{360}×pi×15×15

                             = \frac{90}{360}×pi×15×15

                             = 56.25pi

2) Bigger sector =  \frac{270}{360}×3.14×15×15

                           = 529.875

2) Smaller sector = \frac{360-270}{360}×3.14×15×15

                             = \frac{90}{360}×3.14×15×15

                             = 176.625

6 0
3 years ago
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