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3 years ago

Is 6^-2 positive or negative?

Mathematics

1 answer:

serious [3.7K]3 years ago

6 0

The 6 is a positive and the 2 is a negative. Basically the answer to the equation would be a negative

6 x -6 = -36

Hope this helps you

-AaronWiseIsBae

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2 years ago

shelia has 5 times more markers then dave and together they have 18 markers how many markers does sheli have?

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2 years ago

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elena-14-01-66 [18.8K]

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2 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

2 years ago

A recipe for beef stew calls for 1 pound of beef and 3 potatoes the recipe is doubled to include 2 pounds of beef and 6 potatoes

Lerok [7]

Pounds of beef and potatoes are in ratio or proportion of $\frac{1}{3}$ .

<u>Step-by-step explanation:</u>

Correct Question: A recipe for beef stew calls for 1 pound of beef and 3 potatoes. The recipe is doubled to include 2 pounds of beef and 6 potatoes. Which proportion represents the situation?

We have , A recipe for beef stew calls for 1 pound of beef and 3 potatoes , i.e.

Number of beef stew calls = 1

Number of potatoes = 3

Now , The recipe is doubled to include 2 pounds of beef and 6 potatoes i.e. for every 2 pounds of beef we have 6 potatoes

⇒ $2/6$

⇒ $\frac{2}{6}$

⇒ $\frac{2}{2(3)}$

⇒ $\frac{1}{3}$

Therefore , Pounds of beef and potatoes are in ratio or proportion of $\frac{1}{3}$ .

4 0

2 years ago

Read 2 more answers