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SashulF [63]
3 years ago
15

How to seperate sand and water

Chemistry
2 answers:
strojnjashka [21]3 years ago
8 0

Answer: Some kind of strainer system

Explanation:

ohaa [14]3 years ago
3 0
Let the water evaporate
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A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W
aliina [53]

Answer:

The salt is barium chloride.

Explanation:

BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX

Moles of barium sulfate =\frac{11.21 g}{233.38 g/mol}=0.0480 mol

According to reaction, 1 mol of barium sulfate is produced from 1 mol of BaX_2.

Then 0.0480 moles will be produced from:

\frac{1}{1}\times 0.0480 mol=0.0480 mol of BaX_2.

Mass of BaX_2 used = 10.00 g

Moles of BaX_2 =\frac{10.00 g}{\text{Molar mass}}[/tex]

0.0480 mol=\frac{10.00}{\text{Molar mass}}

Molar mass of BaX_2 = 208.33 g/mol

The nearest answer to our answer is BaCl_2=208.2 g/mol.

The correct answer barium chloride with molar mass of 208.2 g/mol.

8 0
3 years ago
The diagram above shows the repeating groups of atoms that make up two samples. Will the properties of the two samples likely be
Fed [463]
Completely off topic but I couldn’t help but notice you play valorant. If your down what’s ur name and tag line?
6 0
3 years ago
Read 2 more answers
Calculate the cell potential, E, for the following reactions at 26.29 °C using the ion concentrations provided. Then, determine
yanalaym [24]

Answer:

I will work only one of the listed equations ... you follow the given example for the remaining reactions. Thank you :-)

Rxn 1: Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s)

a) E(Pt⁺²/Fe°) = - 1.668v

b) Process is Non-spontaneous if E(cell) < 0

Explanation:

Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s) ⇔

Pt°(s)|Pt⁺²[0.057M]║Fe⁺²[0.006M]|Fe°(s)

As written, Pt° is shown undergoing oxidation with Fe⁺² undergoing reduction. Applying the reduction potentials to the analytical equations for E(cell) and ΔG(cell) gives E(Pt/Fe⁺²) < 0 and ΔG(Pt/Fe⁺²) > 0 which indicate a non-spontaneous process. The following supports this conclusion.

E°(Fe⁺²) = -0.44v

E°(Pt⁺²) = +1.20v

E°(Pt/Fe⁺²) =E°(Redn) - E°(Oxidn) =E°(Fe⁺²) - E°(Pt⁺²)

= -0.44v - (+1.20v) = - 1.64v

[Fe⁺²] = 0.0066M

[Pt⁺²] = 0.057M

n = electrons transferred = 2

E(nonstd) = E°(std) - (0.0592/n)logQ);

Q = [Pt⁺²]/[Fe⁺²]

= -1.64v - (0.0592/2)log[0.057M]/[0.006M]v = -1.668v

Also, if ΔG(cell) > 0 => indicates non-spontaneous process

ΔG(Pt/Fe⁺²) = - nFE = -(2)(96,500Coulombs)((-1.664v) > 0 Kj => nonspontaneous rxn. (1 Coulomb-volt = 1 Kilojoule)

7 0
3 years ago
Briefly explain in your own words why the bond angle increases as the number of electron groups decreases
tekilochka [14]

Answer:

i) The bond angle decreases due to the presence of lone pairs, which causes more repulsion on the bond pairs and as a result, the bond pairs tend to come closer. ii) The repulsion between electron pairs increases with an increase in electronegativity of the central atom and hence the bond angle increases.

Explanation:

4 0
2 years ago
Which power source uses the earth’s internal heat?
Nataly_w [17]

Answer:

Its geothermal energy.

Explanation:

hope this helps

5 0
3 years ago
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