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Gennadij [26K]
3 years ago
7

Calculate the pH and fraction of dissociation (

Chemistry
1 answer:
ELEN [110]3 years ago
3 0
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A solution is prepared by dissolving 27.0 g of urea [(NH2)2CO], in 150.0 g of water. Calculate the boiling point of the solution
andrew11 [14]

<u>Answer:</u> The boiling point of solution is 101.56°C

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure water = 100°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 0.52°C/m.g

m_{solute} = Given mass of solute (urea) = 27.0 g

M_{solute} = Molar mass of solute (urea) = 60 g/mol

W_{solvent} = Mass of solvent (water) = 150.0 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=1\times 0.52^oC/m\times \frac{27\times 1000}{60\times 150}\\\\\text{Boiling point of solution}=101.56^oC

Hence, the boiling point of solution is 101.56°C

5 0
4 years ago
Gold atoms can be identified based on the number of which subatomic particles?
olganol [36]

Answer:B

Explanation:

6 0
3 years ago
How many moles of Li would react with 4 moles of MgBr₂ in the reaction
ad-work [718]

Answer:

two may be the answer (2)

3 0
2 years ago
How many valence electrons does each of the following atoms have?
Zolol [24]
Which atoms?  ~~~~~~~~~~~~~~~~~~~~~~~~~`
6 0
4 years ago
Which of the following best helps to account for the fact that the F- ion is smaller than the O2- ion?
katrin [286]

Answer: Option (B) is the correct answer.

Explanation:

Both oxygen and fluorine are period 2 elements and when we move across a period then there occurs a decrease in atomic size of the atoms. Hence, the atomic radius of a neutral fluorine atom is smaller than a neutral oxygen atom.

Moreover, atomic number of fluorine is 9 and it has higher nuclear charge due to which it will cause more attraction of electrons. As a result, size of a fluorine ion will be smaller.  

On the other hand, size of oxygen atom is larger and has small nuclear charge due to which attraction of electrons by its nucleus will not be strong enough. Hence, the size of O^{2-} will be larger.

Thus, we can conclude that the statement F^{-} has a larger nuclear charge than O^{2-} has, is correct for the fact that the F^{-} ion is smaller than the O^{2-} ion.

3 0
4 years ago
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