Answer:
An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities inelastic collisions.
Explanation:
Suppose two similar trolleys are traveling toward each other with equal speed. They collide, bouncing off each other with no loss in speed. This collision is perfectly elastic because no energy has been lost. In reality, examples of perfectly elastic collisions are not part of our everyday experience. Some collisions between atoms in gases are examples of perfectly elastic collisions. However, there are some examples of collisions in mechanics where the energy lost can be negligible. These collisions can be considered elastic, even though they are not perfectly elastic. Collisions of rigid billiard balls or the balls in Newton's cradle are two such examples.
For the work, applicate formula:
According our data:
W = 12000 N * 1,5 m
W = 18000 J
The work done is <u>18000 Joules.</u>
<u><em>Answer</em></u>
A) 1,347.5 Joules
B) 22.49 m/s
<u><em>Explanation</em></u>
<u>Part A</u>
The work done by the gravity is known as potential energy.
It is given by;
P.E = mgh
Where m is mass, g is acceleration due to gravity and h is the vertical height.
P.E = 5.5 × 9.8 ×25
= 1,347.5 Joules.
<u>Part B</u>
Using the Newton's third Law of motion,
V² = U² +2as
Where v is final velocity, u is the initial velocity, and s is the displacement of the stone.
V² = 4² + (2×9.8×25)
= 16 + 490
= 506
V = √506
= 22.49 m/s
Answer:
E = 2.5 x 10⁻¹⁴ J
Explanation:
given,
diameter = 1.33 x 10⁻¹⁴ m
mass = 6.64 x 10⁻²⁷ kg
wavelength is equal to diameter
de broglie wavelength equal to diameter
v = 7.5 x 10⁶ m/s
Kinetic energy is equal to
E = 2.5 x 10⁻¹⁴ J
Answer:
250N
Explanation:
weight = Mass(in kg) × Gravitational field strength
25 × 10 = 250N
