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4 years ago

A horizontal line on a distance-time graph means the object is

1 answer:

6 0

At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change.

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A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen

Liula [17]

Answer:

option D

Explanation:

given,

wavelength = 600 nm

width of separation = 0.02 mm

L = 5 m

for mth order maxima

$d \times \dfrac{y_m}{L}=m\lambda$

for (m+1)th order maxima

$d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda$

now,

$y_m=\dfrac{mL\lambda}{d}$ and

$y_{m+1}=\dfrac{(m+1)L\lambda}{d}$

hence,

$\Delta y = y_{m+1} - y_m$

$\Delta y =\dfrac{L\lambda}{d}$

$\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}$

$\Delta y =0.15\ m$

$\Delta y =15\ cm$

hence, the correct answer is option D

4 0

4 years ago

The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 290 V, which charges a capacitor.

Margaret [11]

Answer:

Therefore the capacitance of the capacitor is 2.38 * 10⁻⁵F

Explanation:

We apply the concepts related to Power and energy stored in a capacitor.

By definition we know that power is represented as

$P = \frac{E}{t}$

Where,

E= Energy

t = time

to find the Energy we have,

$E = P*t$

$P = 1*10^5Wt = 10*10^{-6}s$

$E= (1*10^5)(10*10^{-6})E = 1.0J$

With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is

$E=\frac{1}{2}CV^2$

$C = \frac{2E}{V^2}\\\\\\\frac{2\times 1 }{290^2 - 3^2\\} \\= 2.38 \times 10^-^5F$

Therefore the capacitance of the capacitor is 2.38 * 10⁻⁵F

3 0

3 years ago

Read 2 more answers

The position of a particle is given by the expression x = 2.00 cos (6.00πt + 2π/5), where x is in meters and t is in seconds det

Nana76 [90]

The position of the particle at time t is
$x(t) = 2.00 \cos (6.00 \pi t+ \frac{2}{5}\pi )$
If we substitute $t=0.330 s$ , we find
$x(0.330 s)=2.00 \cos (6.00 \pi (0.330 s) + \frac{2}{5} \pi)=$
$=2.00 \cos (1.98 \pi + 0.40 \pi )=2.00 \cos (2.38 \pi) =$
$=2.00 \cdot (-0.72)=-1.45 m$

8 0

3 years ago

what is the lowest velocity vmin that a charged particle can have and still emit cherenkov radiation in the aerogel?

allochka39001 [22]

Actually the velocity of a charged particle varied based upon the medium its travelling. But, aerogel is a common medium for detecting Cherenkov radiation.

When a charged particle, most frequently an electron, moves faster than light across a dielectric (may be electrically polarized) medium, Cherenkov radiation is produced. A common radiator for Cherenkov detectors is silica aerogel. It is a very transparent, low-density material with a refractive index (n) that ranges from n 1.001 for gaseous phases to n 1.3 for condensed phases. The speed needs to be higher than 2.25 108 m/s in order to produce the particle. However, there is no specific fixed velocity for a charged particle for this phenomemon to happen in aerogel.

Learn more about Cherenkov radiation brainly.com/question/17157599

#SPJ4

3 0

2 years ago

Which of the following does Bernoulli's principle help to explain?

Anon25 [30]

I would say B surface tension

6 0

3 years ago

Read 3 more answers