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Nadya [2.5K]
2 years ago
11

The lungs are located in the chest true or false

Physics
2 answers:
jarptica [38.1K]2 years ago
8 0
That is False they are actually located in your stomach area
xxTIMURxx [149]2 years ago
3 0

Answer:

True

Explanation:

The lungs are located on either side of the breastbone in the chest cavity and are divided into five main sections (lobes). The lungs are responsible for removing carbon dioxide from the blood and adding oxygen to it.

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Communicating results allows scientists to learn from each other's results.
sveta [45]

True, scientists often talk to each other to figure out if their results were similar and what they could have done better.

Although, talking to other scientists does have risks, other scientists could copy your work and further better it.

So, your final answer is TRUE, sorry for the long answer, I needed to have a word count about 20 characters and then I got carried away! lol

3 0
3 years ago
Read 2 more answers
A study group is meeting to prepare for an upcoming social studies test on the Civil War. Which question would you
Rainbow [258]

Answer:

What were the most important reasons that the Civil War started?

Explanation: i got it correct

4 0
3 years ago
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Acid rain is formed when chemicals in the air get into rain and up the acidity levels.
tester [92]
False! Because the acid rain it becomes a chemicals it does not air get into the rain and up the acidity levels.
Hope it helped you.

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:)
5 0
3 years ago
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During each cycle, a refrigerator ejects 610 kJ of energy to a high-temperature reservoir, and takes in 505 kJ of energy from a
jenyasd209 [6]

Answer

A. the work done on the refrigerant in each cycle is 105kJ

B the coefficient of performance of the refrigerator is 4.8

Explanation

Given data

Work done at high temperature T2 Qh=610kJ

Work done at low temperature T1 Ql=505kJ

We know that the net work done by the refrigerator is expressed as

Wnet= Qh-Ql

=610-505

=105kJ

Also we know that the coefficient of performance is expressed as

COP= Ql/Wnet

COP= 505/105

= 4.8

8 0
2 years ago
Please help if you can.
VMariaS [17]

Initially there were 10 bulbs of 60 Watt power

So total power of all bulbs = 60 * 10 = 600 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = P * t

E = 600 * 4 = 2400 Wh

E = 2.4 kWh

now we have total power consumed in 1 year

E = 365 * 2.4 = 876 kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P_1 = 876 * 10 = 8760 cents = $87.60

Now if all 60 Watt bulbs are replaced by 30 Watt bulbs

So total power of all bulbs = 30 * 10 = 300 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = P * t

E = 300 * 4 = 1200 Wh

E = 1.2 kWh

now we have total power consumed in 1 year

E = 365 * 1.2 = 438 kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P_1 = 438 * 10 = 4380 cents = $43.80

total money saved in 1 year

Savings = 87.6 - 43.8 = $43.80

3 0
3 years ago
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