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nalin [4]
3 years ago
13

A person is pulling their 20 kg luggage using the luggage handle. The handle is at an angle of 56 degrees above the horizontal.

If the person is pulling with a force of 71 N, what is the horizontal acceleration of the luggage (Ignore all friction)
3.19 m/s^2
1.99 m/s^2
0.74 m/s^2
1.02 m/s^2
Physics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

The answer to your question is:  a = 1.99 m/s²

Explanation:

Data

mass = 20 kg

angle = 56°

Force = 71 N

horizontal acceleration = ?

Process

Find the horizontal force

                                           cos Ф = adjacent side / hypotenuse

                                          adjacent side = hypotenuse x cosФ

                                          adjacent side = 71 x cos 56

                                          a.s. = 39.70 N

Newton's second law

                                  F = ma

                                  a = F/m

                                 a = 39.7 / 20

                                  a = 1.99 m/s²

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Answer:

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Explanation:

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\Delta V_T = \Delta V_l - \Delta V_c

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Then replacing with the previous equation we have:

\Delta V = \beta_l V_0 \Delta T- \beta_c V_0 \Delta T

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6 0
3 years ago
Work is done on a locked door that remains closed while you try to pull it open. True False.
dsp73

Answer:False

Explanation:

Work is being done on a body when it causes displacement of body on the application of force

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When we pull the door by a force it causes zero displacements of the door. So we can say that work done on it is zero.

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allsm [11]

Answer:

41.2°

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