PLEASE HELP INEQUALITYS!!

Find the vertical asymptote(s) of f of x equals quantity 4 x squared plus 3x plus 6 end quantity over quantity x squared minus 3

siniylev [52]

The vertical asympototes of f(x) are at x = -6 and x = 6

Step-by-step explanation:

To find the vertical asymptote(s) of a rational function,

Equate the denominator by 0
Solve it for x
If x = a, then the vertical asymptote is at x = a

∵ $f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}$

- Equate the denominator x² - 36 by 0

∵ x² - 36 = 0

- Add 36 to both sides

∴ x² = 36

- Take √ for both sides

∴ x = ± 6

∴ There are vertical asymptotes at x = -6 and x = 6

The vertical asympototes of f(x) are at x = -6 and x = 6

Learn more:

You can learn more about the asymptotes in brainly.com/question/6459599

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4 0

3 years ago

Find the slope of the line below using rise/run.<br>

QveST [7]

Answer:

A, 2/3

Step-by-step explanation:

you rise 2 and run 3

6 0

3 years ago

Read 2 more answers

PLEASE SOLVE THIS :(<br>

Lesechka [4]

Answer:

10.5 %

<u>Skills needed: Financial Math Essentials</u>

Step-by-step explanation:

1) First, before getting started, let's assume the price of the product is $x$ . This variable will be used a lot throughout the problem ( $x$ ).

2) Marking a price above means increasing the price in order to make money off of the purchased product. When raising something by $y$ percent, the new price would be $x + \frac{y}{100}*x$ .

---> In this case, the price increased by $\textbf{30}$ percent.

This means that it would be: $x+\frac{30}{100}x = x+0.3x=1.3x$

New price is: $1.3x$

3) The shopkeeper is then offering a $\textbf{15}$ percent discount off of this marked price. When offering a $b$ percent discount price, the new price (with discount), expressed algebraically is: $a-\frac{b}{100}a$