Question

A bar slides vertically between two conducting rails without friction in a magnetic field. The rails are connected via a resistor. The bar reaches a constant velocity and slides for 2m. How much energy is dissipated in the resistor during these 2m's

Answer 1

Answer:

The energy dissipated is  $E = 9.8 J$

Explanation:

From the question we are told that

    The distance covered at constant velocity d =  2 m  

      The velocity is  $v = 1.5 \ m/s$

Generally at constant velocity the magnetic  force on the bar is mathematically represented as

         $F = m * g$

substituting values

        $F = 0.5 * 9.8$

        $F = 4.9 \ N$

The energy dissipated is mathematically evaluate as

         $E = F * d$

 substituting the value

         $E = 4.9 * 2$

        $E = 9.8 J$