Answer:
364.4 J
Explanation:
I = Moment of inertia of the forearm = 0.550 kgm²
v = linear velocity of the ball relative to elbow joint = 17.1 m/s
r = distance from the joint = 0.470 m
w = angular velocity
Using the equation
v = r w
17.1 = (0.470) w
w = 36.4 rad/s
Rotational kinetic energy of the forearm is given as
RKE = (0.5) I w²
RKE = (0.5) (0.550) (36.4)²
RKE = 364.4 J
<span>Weight of block, Wb = mass*gravity = 50*9.8 = 490 N</span>
Since block is being pulled up by a 13-degree slope
Therefore, Force which is acting parallel to the slop:
<span> F p =490 Sin </span>
= 110.2N
Force which is acting perpendicular to the slope:
<span> Fv =490 Cos</span> = 477.4 N
Net force can be given as follows:
<span>F n = (250 - 110.2 - 0.2*</span>477.4) N
<span>Fn=44.3N</span>
Now acceleration is given by the ratio of force to mass
<span>a = Fn/m</span>
<span>=44.3/50 = 0.89 ms^<span>-2</span></span>
Out of the following given choices;
a. decelerate; accelerate
b. accelerate; decelerate
c. stop; accelerate
d. decelerate; stop
<span>The answer is B. This is because
the cold front usually rotates around the warm front as cold air mass coverage
in the low-pressure system. This causes the cold air mass to accelerate to
catch up with the warm front. When an occluded front ( that is the boundary
that separates the older cool air mass already in place from new incoming cold
air mass), that the system decelerates. </span>
Answer:
it's B I think I did this the other day tbh sorry if it's wrong btw hope this helps
Answer:
"we both attract each other with the same force but we know that attraction between two bodies depends upon their mass, greater the mass of two bodies is the force of attraction between them"(got this off the internet).
