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quester [9]
2 years ago
8

A net force of 2070N acts on a car with a mass of 1350 kg. What is the acceleration of the car?

Physics
1 answer:
emmasim [6.3K]2 years ago
8 0

Answer:

Below

Explanation:

To find the acceleration of the car, we can use this formula :

     acceleration = net force / mass

     acceleration = 2070 N / 1350 kg

     acceleration = 1.53333 m/s^2

     acceleration = 1.53 m/s^2

Hope this helps!

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2. An alternating current is represented by the equation I=20sin 100mt.
Sladkaya [172]

Explanation:

The general equation of an AC current is given by :

I=I_o sin\omega t

Where

I₀ is the peak value of current

\omega is angular frequency

As\ \omega=2\pi f

So,

f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz

We know that,

I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.

3 0
2 years ago
You need to produce a set of cylindrical copper wire 3.5 m long that will have a
vazorg [7]

Solution :

We know, resistance is given by :

R = \dfrac{\rho l}{A}

A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2

Now, we know mass of wire is given by :

Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram

Hence, this is the required solution.

8 0
3 years ago
Calculate the wavelength of an orange light wave with a frequency of 5.085 x 10^14 Hz. The speed of light is 3.0 x 10^8 m/s.
Margarita [4]

Answer:

5.9 x 10⁻⁷m

Explanation:

Given parameters:

Frequency = 5.085 x 10¹⁴Hz

Speed of light  = 3.0 x 10⁸m/s

Unknown:

Wavelength of the orange light  = ?

Solution:

The wavelength can be derived using the expression below;

            wavelength  = \frac{v}{f}

v is the speed of light

f is the frequency

            wavelength  = \frac{3 x 10^{8} }{5.085 x 10^{14} }   = 5.9 x 10⁻⁷m

3 0
3 years ago
Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di
Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, u=20m/s

And the mass of the car is, m=1000 kg

The total distance covered by the car before stop, s=45m

And the final speed of the car is, u=0m/s

Now initial kinetic energy is,

KE_{i}=\frac{1}{2}mu^{2}

Substitute the value of u and m in the above equation, we get

KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J

Now final kinetic energy is,

KE_{f}=\frac{1}{2}mv^{2}

Substitute the value of v and m in the above equation, we get

KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN

Here, the force is negative because the force and acceleration in the opposite direction.

6 0
3 years ago
The Graph above shows the speed of a car traveling in a straight line as a function of time. The car accelerates uniformly and r
devlian [24]

Answer:

Where is the graph??

If a car travels from zero to 4 m/s ins 8 sec

a = 4 / 8 = .5 m/s^2

V (2) = 2 * .5 = 1 m/s after 2 sec

S = V t + 1/2 a t^2

S = 1 * 3.9 + 1/2 * 1/2 *3.9^2 = 3.9 + 3.80 = 7.70 m   from 2 to 5.9  sec

Check:

Total distance traveled = 1/2 a t^2 = 5.9^2 / 4 = 8.70 m

Distance traveled in 2 sec = 1/2 * 1/2 * 4 = 1 m

Total distance from 2 to 5.9 = 8.7 - 1 = 7.7 m agreeing with thw above

3 0
2 years ago
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