All categories

2 years ago

A net force of 2070N acts on a car with a mass of 1350 kg. What is the acceleration of the car?

Physics

1 answer:

emmasim [6.3K]2 years ago

8 0

Answer:

Below

Explanation:

To find the acceleration of the car, we can use this formula :

acceleration = net force / mass

acceleration = 2070 N / 1350 kg

acceleration = 1.53333 m/s^2

acceleration = 1.53 m/s^2

Hope this helps!

You might be interested in

What do you mean by resistance of conductor?state it’s unit.

dalvyx [7]

Answer:

its unit is Ohm

Explanation:

Resistance means material which resist the passing current through it and the value of resistance says how much the material is resisting the current and it temperature dependent and the unit is Ohm.

7 0

3 years ago

Circuit diagram showing three resistors in series with an ammeter,a cell and a switch

docker41 [41]

Answer:

the mayflower

Explanation:

4 0

3 years ago

A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long

Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

$W=-\mu mg\times l$

Put the value into the formula

$W=-0.30\times62\times9.8\times3.50$

$W=-637.98\ J$

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

$K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}$

$\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}$

Final potential energy is zero

So, $\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2$

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl$

Put the value into the formula

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50$

$v_{2}=\sqrt{2\times55.915}$

$v_{2}=10.57\ m/s$

The speed of skier is 10.57 m/s.

Hence, (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0

3 years ago

What's the equivalent resistance to the resistances shown? A) 5 B) 6 C) 2 D) 3

PIT_PIT [208]

From A to B its 5 ohm.
above shown 6 and 12 ohm resistors are in parallel to short circuit hence their equivalent resistance is zero.
(Current doesnt flow through a resisstor if there is a Short circuit alternate.

6 0

3 years ago

Alguien me puede ayudar con esa tabla

Scilla [17]

私は英語がわかりません sorry pls translate

7 0

3 years ago