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3 years ago

Models of four atoms are shown as figures A, B, C, and D. Which two atoms represent isotopes of the same element?

Physics

2 answers:

nirvana33 [79]3 years ago

6 0

ace can you quit the smart talk and please answer in a necessary tone please fam.

zvonat [6]3 years ago

3 0

The identity of the element is determined by the number of protons
in the nucleus of each atom.

If two atoms have the same number of protons in their nucleii
(nucleuses) but different numbers of neutrons, then they're both
atoms of the same element, but their atomic masses are different,
and they're called isotopes of the element.

In the picture, atoms 'A' and 'B' each have 3 protons in the nucleus,
so they're both atoms of Lithium. But the number of neutrons is
different, so 'A' and 'B' are different isotopes of Lithium.

Also in the picture, atoms 'C' and 'D' each have 4 protons in the
nucleus, so they're both atoms of Beryllium. But the number of
neutrons is different, so 'C' and 'D' are different isotopes of Beryllium.

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Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge

kramer

Answer:

E = 440816.32 N/C

Explanation:

Given data:

Three point charge of charge equal to +3.0 micro coulomb

fourth point charge = - 3.0 micro coulomb

side of square = 0.50 m

$K =1/4 \pi \epsilon_0 = 8.99 \times 10^9$ N.m^2/c^2

Due to having equal charge on center of square, 2 charge produce equal electric field at center and other two also produce electric field at center of same value

So we have

$E_1 + E_3 = 0$

$E =E_2 + E_4$

$E = 2 E_2$

[ $E_2 =\frac{2\times k \times q}{r^2}$

[ $r= \frac{(0.5^2 + 0.5^2)^2}{2} = 0.35 m$ ]

plugging all value

$E = 2 E_2$

$E = 2 E_2 =\frac{2\times k \times q}{r^2}$

$E = \frac{2 \times 8.99 \times 10^93\times 10^{-6}}{0.35^2}$

E = 440816.32 N/C

3 0

3 years ago

Read 2 more answers

A football player kicks a ball horizontally off a hill with an initial velocity of 42.0 m/s. It travels a horizontal distance of

damaskus [11]

Explanation:

.........................

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3 years ago

Show that the units N/kg can be written using only units of meters (m) and second (s). Is this a unit of mass ,acceleration or f

nikdorinn [45]

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3 years ago

Significant digits show the _____ of measurements and calculations.

SashulF [63]

Significant digits show the precision of measurements and calculations

7 0

3 years ago

A ball is launched with initial speed v from ground level up a frictionless slope (This means the ball slides up the slope witho

amid [387]

Answer:

hmax = 1/2 · v²/g

Explanation:

Hi there!

Due to the conservation of energy and since there is no dissipative force (like friction) all the kinetic energy (KE) of the ball has to be converted into gravitational potential energy (PE) when the ball comes to stop.

KE = PE

Where KE is the initial kinetic energy and PE is the final potential energy.

The kinetic energy of the ball is calculated as follows:

KE = 1/2 · m · v²

Where:

m = mass of the ball

v = velocity.

The potential energy is calculated as follows:

PE = m · g · h

Where:

m = mass of the ball.

g = acceleration due to gravity (known value: 9.81 m/s²).

h = height.

At the maximum height, the potential energy is equal to the initial kinetic energy because the energy is conserved, i.e, all the kinetic energy was converted into potential energy (there was no energy dissipation as heat because there was no friction). Then:

PE = KE

m · g · hmax = 1/2 · m · v²

Solving for hmax:

hmax = 1/2 · v² / g

4 0

4 years ago