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3 years ago

Kjkrenv rejfkrnfkej erjfnkejrfn jnefkjnfk jekfnrfkj

Physics

2 answers:

Umnica [9.8K]3 years ago

8 0

Answer:

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Explanation:vjrhvbhlwrvbiewyvboiewbycoivyewvobiwelb

aleksandrvk [35]3 years ago

7 0

Answer: you should become an author

Explanation:

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Work is the product of force and an object's

Neporo4naja [7]

Answer:

C. displacement

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Two waves overlap producing a new wave that exhibits destructive

suter [353]

Answer:B

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3 years ago

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¿Cuál es la masa de un objeto cuya masa es de 400 J y energía cinética de 107J?

Pachacha [2.7K]

Answer:

Mass, m = 125 kg

Explanation:

Let us assume that the question says, "What is the mass of an object whose velocity is 400 m/s and the kinetic energy of 10⁷ J.

The kinetic energy of an object is :

$K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^7}{(400)^2}\\\\m=125\ kg$

So, the mass of the object is 125 kg.

3 0

3 years ago

A box is sitting on a 2 m long board at one end. A worker picks up the board at the end with the box so it makes an angle with t

Vlada [557]

Answer:

Explanation:

When the box is on the ramp , component of its weight along the ramp

= mg sinθ

Friction force acting on it in upward direction

=μ mg cosθ

For sliding

μ mg cosθ < mg sinθ

μ cosθ < sinθ

.5 x cos35 < sin35

.41 < .57

So the box will slide

When sliding starts , kinetic friction acts

Net force in downward direction

mgsinθ - μ mg cosθ

acceleration

= gsinθ - μ g cosθ

= 5.62 - .3 x 9.8 x cos35

= 5.62 - 2.4

= 3.22 m /s²

3 0

3 years ago

The maximum wavelength that an electromagnetic wave can have and still eject electrons from a metal surface is 542 nm. What is t

Veseljchak [2.6K]

Answer:

2.295 eV

Explanation:

maximum wavelength, λ = 542 nm = 542 x 10^-9 m

The work function of the metal is defined as the minimum amount of energy falling on the metal so that the photo electrons just ejects the surface of metal.

$W_{o}=\frac{hc}{\lambda }$

where, h is the Plank's constant and c be the speed of light

h = 6.634 x 10^-34 Js

c = 3 x 10^8 m/s

$W_{o}=\frac{6.634\times 10^{-34}\times 3\times 10^{8}}{542\times10^{-9} }$

$W_{o}=3.67\times 10^{-19} J=\frac{3.67\times 10^{-19}}{1.6\times 10^{-19}} eV$

Wo = 2.295 eV

Thus, the work function of this metal is 2.295 eV.

5 0

3 years ago