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IceJOKER [234]
3 years ago
7

Mass stays the for an object even when or gravitational forces change the of the object.​

Physics
1 answer:
Yuri [45]3 years ago
3 0

Answer:

For some reason it doesn't let me type it in here so the answer is in the comment box!

I hope this will help you!:)

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Which is the BEST definition of refraction? A) Light or sound waves change direction. B) Light or sound waves bounce off a mediu
melisa1 [442]
The answer to this is A. this is because, refraction with a light or sound wave changing its direction involve propagation,(in which propagation is the change in direction of a light or sound wave)


4 0
3 years ago
Read 2 more answers
1. The picture below shows Jamal pushing with a 100-Newton (N) force on a large box. Neither
r-ruslan [8.4K]

Answer:

100 newtons

Explanation:

Given,

Jamal pushing a large box by a force, F = 100 N

Work done on the large box is, W = 0

It is because the applied force is less than the force of the friction between the two surfaces.

Yet, there will be a force that is exerted by the large box on Jamal.

According to newton's third law of motion, every action has an equal and opposite reaction. The reaction force is in the direction opposite to the force of action. But, their magnitude remains the same.

                                        F_{a} =-F_{r}

Hence, If the action force is 100 N, then the reaction force should be in 100 N

4 0
3 years ago
Read 2 more answers
Needddd helppppppp!!!
yulyashka [42]

Answer:

2/9 times as strong.

Explanation:

From the question given above, the following assumptions were made:

Initial mass of 1st planet (M₁ ) = M

Initial mass of 2nd planet (m₁ ) = m

Initial distance apart (r₁) = r

Initial Force of attraction (F₁) = F

Final mass of 1st planet (M₂) = 2M

Final mass of 1st planet (m₂) = constant = m

Final distance apart (r₂) = 3r

Final force of attraction (F₂) =?

Next, we shall obtain an expression to determine the new force. This can be obtained as follow:

F = GMm / r²

Cross multiply

Fr² = GMm

Divide both side by Mn

G = Fr² / Mm

Since G is constant, then we have

F₁r₁² / M₁m₁ = F₂r₂² / M₂m₂

Finally, we shall determine the new force as follow:

Initial mass of 1st planet (M₁ ) = M

Initial mass of 2nd planet (m₁ ) = m

Initial distance apart (r₁) = r

Initial Force of attraction (F₁) = F

Final mass of 1st planet (M₂) = 2M

Final mass of 1st planet (m₂) = constant = m

Final distance apart (r₂) = 3r

Final force of attraction (F₂) =?

F₁r₁² / M₁m₁ = F₂r₂² / M₂m₂

Fr² / Mm = F₂ × (3r)² / 2M × m

Fr² / Mm = F₂ × 9r² / 2Mm

Cross multiply

Fr² × 2Mm = F₂ × 9r² × Mm

Divide both side by 9r² × Mm

F₂ = Fr² × 2Mm / 9r² × Mm

F₂ = F × 2 / 9

F₂ = 2/9 F

Thus, the new force is 2/9 times the original force i.e 2/9 times as strong.

4 0
3 years ago
A force of 20N pushes an object of mass 5.0kg along a rough surface of 5.0N​
Alika [10]

Answer:

I'm sorry, I don't think there is any answer to give seeing as no question has been asked

7 0
3 years ago
Read 2 more answers
A student walks 100 m East and 100 m North. What is their distance traveled?
vichka [17]

--  The student's distance traveled is 200 meters.

--  The student's displacement is 141 meters Northeast.

5 0
3 years ago
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