1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verdich [7]
4 years ago
11

A ball is launched with initial speed v from ground level up a frictionless slope (This means the ball slides up the slope witho

ut rolling). The slope makes an angle θ with the horizontal. Using conservation of energy, find the maximum vertical height hmax to which the ball will climb.
Physics
1 answer:
amid [387]4 years ago
4 0

Answer:

hmax = 1/2 · v²/g

Explanation:

Hi there!

Due to the conservation of energy and since there is no dissipative force (like friction) all the kinetic energy (KE) of the ball has to be converted into gravitational potential energy (PE) when the ball comes to stop.

KE = PE

Where KE is the initial kinetic energy and PE is the final potential energy.

The kinetic energy of the ball is calculated as follows:

KE = 1/2 · m · v²

Where:

m = mass of the ball

v = velocity.

The potential energy is calculated as follows:

PE = m · g · h

Where:

m = mass of the ball.

g = acceleration due to gravity (known value: 9.81 m/s²).

h = height.

At  the maximum height, the potential energy is equal to the initial kinetic energy because the energy is conserved, i.e, all the kinetic energy was converted into potential energy (there was no energy dissipation as heat because there was no friction). Then:

PE = KE

m · g · hmax = 1/2 · m · v²

Solving  for hmax:

hmax = 1/2 · v² / g

You might be interested in
Explain how you should walk
hammer [34]

Answer:

A step by step to walk

Explanation:

One- Make sure your shoes are tied so that you dont trip

Two- Make sure your way is a cleared path so you dont fall or even hurt yourself

three- use both set of lets to go in any direction you want.

Four- when walking make sure to try and keep a steedy pace so that both set of legs are going up and down but in harmony

3 0
3 years ago
Read 2 more answers
A 4.25-g bullet traveling horizontally with a velocity of magnitude 375 m/s is fired into a wooden block with mass 1.12 kg, init
Tems11 [23]

Answer:

0.9904 m/s

Explanation:

To solve this problem we need to use the conservation of momentum:

m1v1 + m2v2 = m1'v1' + m2'v2'

Using this equation, we have:

m_bullet*v_bullet = m_bullet_after*v_bullet_after + m_block*v_block

0.00425 * 375 = 0.00425 * 114 + 1.12 * v_block

1.12 * v_block = 1.5938 - 0.4845

1.12 * v_block = 1.1093

v_block = 1.1093 / 1.12

v_block = 0.9904 m/s

3 0
4 years ago
Read 2 more answers
5. A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 6400 m away?
EastWind [94]

Answer:

8.89 secs

Explanation:

720m = 1 sec

6400m = ?

6400/720 = 8.89 secs

8 0
3 years ago
Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with
Mekhanik [1.2K]

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

8 0
4 years ago
Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.
tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

T = 2\pi \sqrt {\dfrac Lg}

Where,

T - period

L - length = 12 inches

g- gravitational acceleration  = \bold {9.8\rm \ m/s^2}

Put the values,

T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191

Now, the angular displacement of the pendulum can be calculated by,

\theta = A\times\rm \  cos(\omega T)

Where,

A- amplitude

\theta - angle  = 75^o

\omega - angular displacement = 2\pi/T = 2.866 m

Put the values and calculate for \omega,

75 = A\times{\rm \  cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches

Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

To know more about Amplitude of pendulum,

brainly.com/question/14840171

4 0
3 years ago
Other questions:
  • The speed of a moving bullet can be determined by allowing the bullet to pass through two rotating paper disks mounted a distanc
    13·1 answer
  • Question 29 of 36
    15·1 answer
  • Recessive Disorder or Disease - How would a child get it?
    12·2 answers
  • Use the SI prefixes in Table 3 of this chapter to convert these hypothetical units of measure into appropriate quantities: a. 10
    12·1 answer
  • Please help!!!!!!!
    14·1 answer
  • PLEASE HEEEEEEELP
    10·1 answer
  • A pair of equal charges are separated by .75 m. There's a 2500 N force acting on them. What is the strength of the charge? Plz e
    6·1 answer
  • A 2.2 kg rat floating in space pushes a piece of cheese away from himself at 10 m/s. The cheese has a mass of 1.1 kg. What is th
    6·1 answer
  • If Earth's gravity pulls an object, causing it to accelerate to the ground, what
    11·1 answer
  • Change 176°F to the Celsius and Kelvin scales. pura batana kese hua fir answer dena plzz​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!