9514 1404 393
Answer:
- x = x+1
- 0 = x+1
- x+1 = x+1
Step-by-step explanation:
1. There will be no solution if the equation is a contradiction. Usually, it is something that can be reduced to 0 = 1.
If we choose to make our equation ...
x = x +1
Subtracting x from both sides of the equation gives ...
0 = 1
There is no value of the variable that will make this be true.
__
2. Something that reduces to x = c will have one solution. One such equation is ...
0 = x+1
x = -1 . . . . subtract 1 from both sides
__
3. Something that reduces to x = x will have an infinite number of solutions.
One such equation is ...
x+1 = x+1
Subtracting 1 from both sides gives ...
x = x . . . . true for all values of x
Answer:
x +3 = x^2 +2x -4
Step-by-step explanation:
Straight substitution of the top expression for y gives you ...
x +3 = x^2 +2x -4
__
This lets you rewrite the equation to standard form as ...
x^2 +x -7 = 0
and find the solutions to be ...
x = (-1±√29)/2
Corresponding y-values will be 3 more than this:
y = (5±√29)/2
Answer:
$1,034.88
Step-by-step explanation:
since he earns time and a half on Saturdays, he gets $23.52 per hour. on Sundays,he earns double time, it is $31.36 per hour. when you multiply his regular rate per hour with 40, you have $627.20. His Saturday rate with 8, $188.16. And his Sunday rate with 7, $219.52. Add all those together, and you have an answer!
hope I helped...
Answer:
teaspoons of cinnamon per cup of sugar.
Step-by-step explanation:
A recipe calls for
cups of sugar for every
teaspoons of cinnamon.
For one cup of sugar;
1 ×
÷
=
×
=
teaspoons of cinnamon will be needed.
Let x = volume of saline solution A,
y = volume of saline solution B.
We're going to set up two equations.
Firstly, x + y = 6. That gives us y = 6 – x (1)
Second, 0.1x + 0.05y = 0.08•6,
or 0.1x + 0.05y = 0.48 (2)
Substitute (1) into (2):
0.1x + 0.05(6 – x) = 0.48
0.1x + 0.3 – 0.05x = 0.48
0.05x + 0.3 = 0.48
Subtract 0.3 from both sides:
0.05x = 0.18
x = 3.6
Then y = 6 – 3.6 = 2.4
So we have to use 3.6 litres of solution A and 2.4 litres of solution B.