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3 years ago

In a certain grocery store, strawberries cost $6.40 per pound ( 6.40 dollars/lb ). What is the cost per ounce?

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Solution:

we are given that

In a certain grocery store, strawberries cost $6.40 per pound ( 6.40 dollars/lb ).

we have been asked to find the cost per ounce?

As we know that

16 oz=1 lb

so we will divide by 16 to get the cost per ounce.

strawberries cost $6.40 per pound so for 1 oz it will cost $=\frac{6.40}{16}= 0.4$ $

Hence cost per ounce is 0.40 $

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saveliy_v [14]

50/50 chance..........

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3 years ago

You know 50*8=400. Explain how that helps you find (-50) (-8).

Afina-wow [57]

Answer:

Both equations equal 400.

(-50)(-8) = 400

50*8 = 400

Step-by-step explanation:

50*8 = 400 helps you find (-50)(-8) because (-a) = a. You simply must remove the parentheses. I hope this helps!

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4 years ago

Reflected across the y-axis, translated down 5 units

koban [17]

Answer:

7y and 7 5x

Step-by-step explanation:

7y and 7x is diffrentOK

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4 years ago

Which value of x is in the solution set of the following inequality? -3+5>17

Tju [1.3M]

Answer:

x = - 5

Step-by-step explanation:

Given

- 3x + 5 > 17 ( subtract 5 from both sides )

- 3x > 12 ( divide both sides by - 3 )

Remembering to reverse the inequality symbol when dividing/ multiplying by a negative quantity.

x < - 4 ← symbol reversed

The value of x that is in the solution set is x = - 5

8 0

3 years ago

The rate of change in sales for Garmin from 2008 through 2013 can be modeled by

Zina [86]

Answer:

a) The model for the sales of Garmin is represented by $S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + 47.112$ .

b) The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.

Step-by-step explanation:

a) The model for the sales of Garmin is obtained by integration:

$S(t) = -0.0972\int {t^{2}} \, dt + 2.136\int {t}\,dt -11.9 \int\,dt$

$S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + C$ (1)

Where $C$ is the integration constant.

If we know that $t = 9$ and $S(t) = 2.9$ , then the model for the sales of Garmin is:

$-\frac{81}{2500} \cdot 9^{3} + \frac{267}{250}\cdot 9^{2}-11.9\cdot (9) + C = 2.9$

$C = 47.112$

The model for the sales of Garmin is represented by $S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + 47.112$ .

b) The average sales of the Garmin from 2008 through 2013 ( $\bar{S}$ ) is determined by the integral form of the definition of average, this is:

$\bar{S} = \frac{1}{13 - 8} \cdot \int\limits^{13}_{8} {S(t)} \, dt$ (2)

$\bar S = \frac{1}{5}\cdot \int\limits^{13}_{8} {\left[-\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2}-11.9\cdot t + 47.112 \right]} \, dt$

$\bar S = \frac{1}{5}\cdot \left[-\frac{81}{10000}\cdot (13^{4}-8^{4}) +\frac{89}{250}\cdot (13^{3}-8^{3}) -\frac{119}{20}\cdot (13^{2}-8^{2}) +47.112\cdot (13-8) \right]$ $\bar{S} = \frac{1}{5}\cdot (-198.167+599.86-624.75+235.56)$

$\bar{S} = 2.5$

The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.

7 0

3 years ago