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netineya [11]
4 years ago
5

BRAINLIEST IF CORRECT MUST USE WORK. Which option is an example of a chemical property?

Chemistry
2 answers:
lakkis [162]4 years ago
7 0

Rusting ability is a chemical property.


Since the act of rusting creates a new material (an oxide), it is a chemical change.  The other three are physical properties, since they do not involve the formation of a new substance.

alexgriva [62]4 years ago
6 0
Rusting ability bc that's an act of chemicals reacting on an object
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Answer:

it will gain electrons to fill its outer shell

Explanation:

This element is boron which has 5 electrons.

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Which of the following compounds is the name of a 5 carbon Allene?
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When studying pea plants, Gregor Mendel made many interesting discoveries and came to a few conclusions about what happens as a
lubasha [3.4K]

Characteristics of pea plants are determined by genes inherited from both the parents.

Option 4.

<h3><u>Explanation:</u></h3>

Gregor Johann Mendel is also called as the father of Genetics. Mendel experimented on the pea plants to determine what happens when different types of pea plants are crossed between themselves and what actually determines the characteristics of the pea plants. After two types of experiments, he came to a conclusion that there are certain substances which he named as '' factors'' which are actually inherited from the parents. He also told that there are certain type of factors which are dominant over the others which he termed as recessive factors. So, the characteristics of the progenies depend on both the factors inherited from both the parents.

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3 years ago
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Something that is  special to you or event that means alot to you

3 0
3 years ago
If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res
baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute = 27.1 g

M_{solute} = Molar mass of solute = 27.1 g/mol

W_{solvent} = Mass of solvent = 100 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m

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8 0
3 years ago
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