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Zigmanuir [339]
3 years ago
6

What would be coordinates of the image(13,570)

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
I cant see the image
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What is the value of the exponital expression below 36 1/2
Vedmedyk [2.9K]
The answer is 6.

36^ 1/2 = the square root of 36 = 6
8 0
3 years ago
Convert the flow rate of 250 gallons per minute (gpm) to a flow rate of gallons per second.
Blizzard [7]

Answer:

multiply by

Convert from Convert to

US gpd US gpm cfm IMP gpd IMP gpm

m3/s 22800000 15852 2119 19000000 13200

m3/min 380000 264.2 35.32 316667 220

m3/h 6333.3 4.403 0.589 5277.8 3.67

liter/sec 22800 15.852 2.119 19000 13.20

liter/min 380 0.2642 0.0353 316.7 0.22

liter/h 6.33 0.0044 0.00059 5.28 0.0037

US gpd 1 0.000695 0.000093 0.833 0.000579

US gpm 1438.3 1 0.1337 1198.6 0.833

cfm 10760.3 7.48 1 8966.9 6.23

Imp gpd 1.2 0.00083 0.00011 1

Step-by-step explanation:

googled it

7 0
3 years ago
Read 2 more answers
A rectangular pyramid has a volume of 160 cubic feet. Find two possible sets of measurements for the base area and height of the
muminat

\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ \cline{1-1} V=160 \end{cases}\implies 160=\cfrac{Bh}{3}\implies 480=Bh \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} 480=&2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 5\\ &8\cdot 60\\ &32\cdot 15 \end{cases}~\hspace{5em}\stackrel{B}{8}\times\stackrel{h}{60}\qquad \qquad \stackrel{B}{32}\times\stackrel{h}{15}

4 0
3 years ago
Mari has a part time job. She earns $6 an hour. She makes at most $207.00 a week. What is the greatest number of hours that she
sergejj [24]

Answer:

If Mary earns 7$ an hour, we need to multiplicate 7$ by the number of hours worked for the entire week so we can get the salary per week.

Step-by-step explanation:

it's correct

8 0
3 years ago
The figures below are rectangles. Which polynomial represents the area of the shaded region? HAVE ALL MY POINTS but answer truth
Aleks04 [339]

Answer:

7x - 1

Step-by-step explanation:

Area of the shaded region = area of the large rectangular - area of the small rectangle

Area of rectangle is given as l*w

Area of the large rectangle = l*w = (x + 5)(x - 1)

Expand

= x(x - 1) +5(x - 1)

= x^2 - x + 5x - 5

Area of large rectangle = x^2 + 4x - 5

Area of small rectangle = l*w = (x + 1)(x - 4)

= x(x - 4) +1(x - 4)

=  x^2 - 4x + x - 4

Area of small rectangle = =  x^2 - 3x - 4

Area of shaded region = (x^2 + 4x - 5) - (x^2 - 3x - 4)

= x^2 + 4x - 5 - x^2 + 3x + 4

Collect like terms

= x^2 - x^2 + 4x + 3x - 5 + 4

= 7x - 1

6 0
3 years ago
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