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Delicious77 [7]
3 years ago
11

hi if anyone is good with extraneous solutions pleaseeeeeee help meeee tessa solves the equation below by first squaring both si

des of the equation√x^2-3x-6=x-1 what extraneous solution does tessa obtain x=
Mathematics
1 answer:
Sergio [31]3 years ago
6 0

Answer:

x = -7/5

Step-by-step explanation:

If we square both sides of the equation, we get:

\sqrt{x^2-3x-6}=x-1\\ (\sqrt{x^2-3x-6})^2=(x-1)^2\\x^2-3x-6=x^2-2x+1\\

Then, solving for x, we get:

x^2-3x-6=x^2-2x+1\\-3x-6=2x+1\\-6-1=2x+3x\\-7=5x\\\frac{-7}{5}=x

So, x is equal to -7/5

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