hi if anyone is good with extraneous solutions pleaseeeeeee help meeee tessa solves the equation below by first squaring both si

Question

2 years ago

11

des of the equation√x^2-3x-6=x-1 what extraneous solution does tessa obtain x=

1 answer:

Sergio [31] · Answer 1 · 2022-06-19T12:12:38+03:00

6 0

Answer:

x = -7/5

Step-by-step explanation:

If we square both sides of the equation, we get:

$\sqrt{x^2-3x-6}=x-1\\ (\sqrt{x^2-3x-6})^2=(x-1)^2\\x^2-3x-6=x^2-2x+1\\$

Then, solving for x, we get:

$x^2-3x-6=x^2-2x+1\\-3x-6=2x+1\\-6-1=2x+3x\\-7=5x\\\frac{-7}{5}=x$

So, x is equal to -7/5