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Vinvika [58]
3 years ago
9

Humorous name for a model T Ford

Physics
2 answers:
AfilCa [17]3 years ago
6 0

Old Grandpy!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


Alex787 [66]3 years ago
3 0

The old girl!

The Old Grandpappy!


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All three windows are the same size.

A has 10 complete waves visible through the window. B has 3, and C has 4.

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Explanation:

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<span>6.67 metros por segundo
~ Haga 800/120 que equivale a 6.67 porque hay 60 segundos en un minuto y hay dos minutos, entonces 60 veces 2 es igual a 180, luego configure su problema
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A reasonable estimate of the moment of inertia of an ice skater spinning with her arms at her sides can be made by modeling most
Oxana [17]

Answer:

A)  I_{total} = 1.44 kg m², B) moment of inertia must increase

Explanation:

The moment of inertia is defined by

     I = ∫ r² dm

For figures with symmetry it is tabulated, in the case of a cylinder the moment of inertia with respect to a vertical axis is

      I = ½ m R²

A very useful theorem is the parallel axis theorem that states that the moment of inertia with respect to another axis parallel to the center of mass is

    I = I_{cm} + m D²

Let's apply these equations to our case

The moment of inertia is a scalar quantity, so we can add the moment of inertia of the body and both arms

      I_{total}=I_{body} + 2 I_{arm}

       I_{body} = ½ M R²

The total mass is 64 kg, 1/8 corresponds to the arms and the rest to the body

       M = 7/8 m total

       M = 7/8 64

       M = 56 kg

The mass of the arms is

      m’= 1/8 m total

      m’= 1/8 64

      m’= 8 kg

As it has two arms the mass of each arm is half

     m = ½ m ’

     m = 4 kg

The arms are very thin, we will approximate them as a particle

    I_{arm} = M D²

Let's write the equation

     I_{total} = ½ M R² + 2 (m D²)

Let's calculate

    I_{total} = ½ 56 0.20² + 2 4 0.20²

    I_{total} = 1.12 + 0.32

    I_{total} = 1.44 kg m²

b) if you separate the arms from the body, the distance D increases quadratically, so the moment of inertia must increase

6 0
4 years ago
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