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Dima020 [189]
3 years ago
11

Young _____ stars would most likely be found in a giant molecular cloud.

Physics
1 answer:
marysya [2.9K]3 years ago
6 0
The correct answer is letter A. red. Young red stars would most likely be found in a giant molecular cloud. Red stars<span> are cooler than the sun, with surface temperatures of 3,500 K for a bright red star</span>
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What is the difference between error and uncertainty?
Andrej [43]
Error is the difference between the true value of the measurand and the measured value.. Uncertainty characterizes the range of values within which the true value is asserted to lie with some level of confidence.

If that doesn’t help here’s the definition of both the terms,

Error:

A mistake

Uncertainty:

the state of being uncertain.
6 0
3 years ago
Which part of the atmosphere is the highest layer in which planes can fly?
Rudiy27

Answer:

the stratosphere

Explanation:

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8 0
4 years ago
Reflection happens when a wave __________ .
bagirrra123 [75]
The answer is C. I just took the test. 

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3 years ago
How do you define radiation (whats the definition for radiation?)​
stiv31 [10]

Answer:

<em>Radiation is energy that comes from a source and travels through space and may be able to penetrate various materials. Light, radio, and microwaves are types of radiation that are called nonionizing.</em>

Explanation:

7 0
3 years ago
Three identical charges q form an equilateral triangle of side a with two charges on the x-axis and one on the positive y-axis.
shusha [124]

Answer:

F_n = k*q*(\frac{2*(y + \frac{\sqrt{3}*a }{2}) }{((y+ \frac{\sqrt{3}*a }{2})^2 + (a/2)^2)^1.5 } +\frac{1}{y^2}  )

Explanation:

Given:

- Three identical charges q.

- Two charges on x - axis separated by distance a about origin

- One on y-axis

- All three charges are vertices

Find:

- Find an expression for the electric field at points on the y-axis above the uppermost charge.

- Show that the working reduces to point charge when y >> a.

Solution

- Take a variable distance y above the top most charge.

- Then compute the distance from charges on the axis to the variable distance y:

                                  r = \sqrt{(\frac{\sqrt{3}*a }{2} + y)^2 + (a/2)^2  }

- Then compute the angle that Force makes with the y axis:

                                 cos(Q) = sqrt(3)*a / 2*r

- The net force due to two charges on x-axis, the vertical components from these two charges are same and directed above:

                                 F_1,2 = 2*F_x*cos(Q)

- The total net force would be:

                                F_net = F_1,2 + kq / y^2

- Hence,

                                F_n = k*q*(\frac{2*(y + \frac{\sqrt{3}*a }{2}) }{((y+ \frac{\sqrt{3}*a }{2})^2 + (a/2)^2)^1.5 } +\frac{1}{y^2}  )

- Now for the limit y >>a:

                              F_n = k*q*(\frac{2*y(1 + \frac{\sqrt{3}*a }{2*y}) }{y^3((1+ \frac{\sqrt{3}*a }{2*y})^2 + (a/y*2)^2)^1.5 }) +\frac{1}{y^2}  )

- Insert limit i.e a/y = 0

                              F_n = k*q*(\frac{2}{y^2} +\frac{1}{y^2})  \\\\F_n = 3*k*q/y^2

Hence the Electric Field is off a point charge of magnitude 3q.

8 0
4 years ago
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