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victus00 [196]
3 years ago
13

the difference between speed and velocity is that A) speed is a vector and requires a direction. B) speed is a vector and requir

es a magnitude. C) velocity is a vector and requires a direction. Eliminate D) velocity is a vector and requires a magnitude.

Physics
2 answers:
jenyasd209 [6]3 years ago
6 0

The correct answer is C. Velocity is a vector and requires a direction.

Explanation:

In physics both speed and velocity are used to study the motion of a body; however, they are slightly different. In the case of speed, this describes the rate of change in position based on distance and time, because of this, speed is based on a magnitude or quantity. On the other hand, velocity is a vector because it does not only includes a change of position but the direction of motion usually based on a specific location reference.

Considering this, it can be concluded the difference between speed and velocity is that "velocity is a vector and requires a direction" because velocity includes both the distance and time (speed) along with the direction while speed focuses only on time and distance.

sattari [20]3 years ago
6 0

The difference between speed and velocity is that C) velocity is a vector and requires a direction

<h3>Further explanation </h3>

Vector is a quantity that has a value and direction

Vector can be symbolized in the form of directed line segments

\large {\boxed {\bold {\overrightarrow{A}}}

while the length of the vector is denoted by | a |

Vectors can be written in the form of sequential pairs which shows their coordinates in the Cartesian plane: a (a₁, a₂)

with length

\large {\boxed {\bold {|a|=\sqrt{a_1^2+a_2^2}  }}

If the direction of the vector is reversed, we get the vector -a which has the same length but in the opposite direction

Operations on vectors include addition and subtraction. Addition of vector a and vector b can be done in a triangular way where the base point of vector b coincides with the endpoint of vector a

The sum of the two is obtained by pulling the line segment from the base point of the vector a to the endpoint of the vector b which results in a new vector c

So a + b = c

If vector a is added by inverse b (-b) then the sum becomes a + (- b) = a-b

If a vector is multiplied by a scalar number (eg denoted by k) then the new vector becomes k | a |.

If k> 0, the new vector is in the direction of vector a, but if k <0 it will be in the opposite direction

A vector has a direction and a magnitude, while a scalar has only a magnitude.

Examples of scalars are: length, mass, time, speed

Examples of vectors are: force, acceleration, velocity

<h3>Learn more </h3>

the average velocity

brainly.com/question/5248528

resultant velocity

brainly.com/question/4945130

the coin velocity

brainly.com/question/13103128

Keywords: vector, speed, velocity

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harkovskaia [24]

Answer:

m = 3 kg

The mass m is 3 kg

Explanation:

From the equations of motion;

s = 0.5(u+v)t

Making t thr subject of formula;

t = 2s/(u+v)

t = time taken

s = distance travelled during deceleration = 62.5 m

u = initial speed = 25 m/s

v = final velocity = 0

Substituting the given values;

t = (2×62.5)/(25+0)

t = 5

Since, t = 5 the acceleration during this period is;

acceleration a = ∆v/t = (v-u)/t

a = (25)/5

a = 5 m/s^2

Force F = mass × acceleration

F = ma

Making m the subject of formula;

m = F/a

net force F = 15.0N

Substituting the values

m = 15/5

m = 3 kg

The mass m is 3 kg

7 0
3 years ago
In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
galina1969 [7]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

5 0
3 years ago
31) The basic concept of how a simple motor works is explained by which statement?
Firdavs [7]

Answer:

When a wire that carries electrical current is placed in a magnetic field the wire experiences a force.

Explanation:

The electric motor is a device which convert electrical energy into mechanical energy  ie when current carrying conductor is placed in magnetic field it experience a force. Flemings left hand rule explains the direction of the current.

The electric motor works by attraction and repulsion of magnetic field.

So the option d explains basic concept of simple motor ie when when current carrying wire is placed in the magnetic field it experience magnetic repulsive force.

5 0
3 years ago
A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr
astraxan [27]

Answer:

x =  0.0734 m = 7.34 cm

Explanation:

First we shall calculate the area of the piston:

Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2

Now, we will calculate the force on the piston due to atmospheric pressure:

Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N

Now, for the compression of the spring we will use Hooke's Law as follows:

F = kx\\

where,

k = spring constant = 3400 N/m

x = compression = ?

Therefore,

<u>x =  0.0734 m = 7.34 cm</u>

8 0
3 years ago
A cylindrical, 0.500-m rod has a diameter of 0.02 m. The rod is stretched to a length of 0.501 m by a force of 3000 N. What is t
Salsk061 [2.6K]

Answer:

Y = 4.775 x 10⁹ Pa = 4.775 GPa

Explanation:

First, we calculate the stress on the rod:

stress = \frac{Force}{Area} = \frac{3000\ N}{\pi r^2}  \\\\stress = \frac{3000\ N}{\pi (0.01\ m)^2}\\\\stress = 9.55\ x\ 10^6\ Pa = 9.55 MPa\\

Now, we calculate the strain:

strain = \frac{Change\ in Length}{Original\ Length}\\\\strain = \frac{0.501\ m - 0.5\ m}{0.5\ m}\\\\strain =  0.002\\

Now, we will calculate the Young's Modulus (Y):

Y = \frac{stress}{strain}\\\\Y = \frac{9.55\ x\ 10^6\ Pa}{0.002} \\

<u>Y = 4.775 x 10⁹ Pa = 4.775 GPa</u>

6 0
3 years ago
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