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Savatey [412]
3 years ago
13

When is a white dwarf formed?

Physics
2 answers:
Anna [14]3 years ago
6 0
When a red giant has insufficient mass it pretty much sheds its outer layer to leave the center core know as the white dwarf
mario62 [17]3 years ago
6 0
After a star sheds its outer layers and forms a planetary nebula it will leave behind a core which is the remnant white dwarf
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A uniform steel rod of cross-sectional area A is attached to rigid supports and is unstressed at a temperature of 458F. The stee
Vedmedyk [2.9K]

Explanation:

As the given rod is attached to rigid supports as a result, the deformation occurring due to the change in temperature will cause stress in the rod.

Let us assume that P is the compressive force in the rod due to change in temperature.

So,        \Delta T = \frac{\sigma_{y}}{E_{a}}

                          = \frac{36 \times 10^{3}}{(29 \times 10^{6} \times 6.5 \times 10^{-6})}

                          = 190.98^{o}F

Now, we will calculate the actual change in temperature as follows.

             \Delta T = 320 - 45 = 275^{o}F

This means that the actual change in temperature is more than required for yielding.

(a)   Formula to calculate yielding stress is as follows.

             \sigma' = \frac{P'}{A}

           \sigma' = -\frac{AE \alpha \Delta T}{A}

                        = -E \alpha \Delta T

                        = -29 \times 10^{6} \times 6.5 \times 10^{-6} \times 275

                        = -51.8375 \times 10^{3} psi

Hence, stress in the bar when temperature is raised to 320^{o}F is -51.8375 \times 10^{3} psi.

(b)  Now, we will calculate the residual stress as follows.

            \sigma_{r} = -\sigma_{y} - \sigma'

           \sigma_{r} = -36 + 51.837 ksi

                          = 15.837 ksi

Therefore, stress in the bar when the temperature has returned to 45^{o}F is 15.837 ksi.

6 0
3 years ago
Read 2 more answers
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