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3 years ago

When is a white dwarf formed?

2 answers:

6 0

When a red giant has insufficient mass it pretty much sheds its outer layer to leave the center core know as the white dwarf

mario62 [17]3 years ago

6 0

After a star sheds its outer layers and forms a planetary nebula it will leave behind a core which is the remnant white dwarf

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The Tour de France is the biggest bicycle race in the world. The race lasts for three weeks and is one of the biggest sporting e

avanturin [10]

Answer:

Yellow, green, polka dot and white jerseys

Explanation:

Tour de France is the biggest bicycle race in the world held at France over a period of 23 days. At the end of each day of racing they give to the certain riders FOUR different colored jerseys:

The yellow jersey is given to the overall winner at each stage, this shows the rider who was the best in the previous stage.
The green jersey is given to the best sprinter of each stage,
The polka dot jersey is given to the rider who first reach the crest of designated hills and mountains at each stage.
The white jersey is given to the fastest rider at each stage under 25 years at the beginning of the racing year.

At the end of the competition, the total points are counted and the different jerseys are given to the overall winners.

5 0

3 years ago

A single-turn square loop carries a current of 16 A . The loop is 15 cm on a side and has a mass of 3.8×10^−2kg . Initially the

DiKsa [7]

Answer:

The minimum magnetic field is 0.078 T.

Explanation:

Given that,

Current = 16 A

Side = 15 cm

Mass $m= 3.8\times10^{-2}\ kg$

Mass each segment in given square loop is

$m=\dfrac{3.8\times10^{-2}}{4}$

We need to calculate the torque due to gravity

Using formula of torque

$\tau_{g}=2mg(\dfrac{L}{2})+mgL$

$\tau_{g}=2mgL$

The torque due to magnetic field

$\tau_{B}=FL$

$\tau_{B}=BIL^2$

The equilibrium condition

$\tau_{B}=\tau_{g}$

Put the value into the formula

$BIL^2=2mgL$

$B=\dfrac{2mgL}{IL^2}$

$B=\dfrac{2mg}{IL}$

Put the value into the formula

$B=\dfrac{2\times\dfrac{3.8\times10^{-2}}{4}\times9.8}{16\times15\times10^{-2}}$

$B=0.078\ T$

Hence, The minimum magnetic field is 0.078 T.

7 0

3 years ago

Liquids with convex meniscus

kobusy [5.1K]

Mercury in a glass tube.

7 0

2 years ago

A train moving with a velocity of 42.9 km/hour North, increases its speed with a uniform acceleration of 0.250 m/s^2 North until

ankoles [38]

Answer:

3658.24m

Explanation:

Hello!

the first thing that we must be clear about is that the train moves with constant acceleration

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

$\frac {Vf^{2}-Vo^2}{2.a} =X$

Vf = final speed =160km/h=44.4m/s

Vo = Initial speed =42.9km/h=11.92m/s

A = acceleration =0.25m/s^2

X = displacement

solving

$\frac {44.4^{2}-11.92^2}{2.(0.25)} =X\\X=3658.24m$

the distance traveled by the train is 3658.24m

5 0

3 years ago

I need help with this question how to solve it for Brass and Cooper

Ksenya-84 [330]

Take into account that density and relative density are given by:

$\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}$

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

$\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}$

Cooper:

$\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}$

3 0

1 year ago