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Savatey [412]
3 years ago
13

When is a white dwarf formed?

Physics
2 answers:
Anna [14]3 years ago
6 0
When a red giant has insufficient mass it pretty much sheds its outer layer to leave the center core know as the white dwarf
mario62 [17]3 years ago
6 0
After a star sheds its outer layers and forms a planetary nebula it will leave behind a core which is the remnant white dwarf
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Describe this picture in 5 words ​
PilotLPTM [1.2K]

Answer:

heathy, people, apple, motivational, together  

Explanation:

7 0
2 years ago
Read 2 more answers
sla’s change in velocity is 30 m/s, and Hazel has the same change in velocity. Which best explains why they would have different
sweet [91]
Because acceleration depends not only on the change in velocity.
It also depends on the time during which the change occurs.
The formula is

Acceleration = (change in velocity) divided by (time for the change) .

Maybe Sla changed his velocity in 3 seconds, but Hazel
took all morning to change hers.  In that case, even though
the amounts of change were equal, the times were different,
so the quotients of (change/time) were different. 
8 0
3 years ago
The diagram shows a 225 N load attached to a moveable pulley.What amount of force is needed to lift the load?
hram777 [196]
I'm happy to know that the diagram shows how it's all set up.
If I could see the diagram, then I could probably do a much
better job with an answer.  As it is ... 'flying blind' as it were ...
I'm going to wing it and hope it's somewhat helpful.

If the pulley is movable, then I'm picturing one end of the rope
tied to a hook in the ceiling, then the rope passing down through
the pulley, then back up, and you lifting the free end of the rope.

A very useful rule about movable and combination pulleys is:
the force needed to lift the load is

            (the weight of the load)
divided by
            (the number of strands of rope supporting the load) .

With the setup as I described it, there are 2 strands of rope
supporting the load ... one on each side of the pulley.  So the
force needed to lift the load is

                                 (250 N) / 2  =  125 N .

6 0
3 years ago
You push
alekssr [168]
45 because you see it in a hot min.
8 0
3 years ago
In Trial II, the same spring is used as in Trial I. Let us use this information to find the suspended mass in Trial II. Use 0.51
Masteriza [31]

Answer:

M_2=0.79kg

Explanation:

From the question we are told that:

Period T=0.517s

Trial 1

Spring constant \mu=117N/m

Period T_1=0.37

Mass m=0.400kg

Trial 2

Period T_2=0.52

Generally the equation for Spring Constant  is mathematically given by

\mu=\frac{4 \pi^2 M}{T^2}

Since

\mu _1=\mu_2

Therefore

\frac{4 \pi^2 M_1}{T_1^2}=\frac{4 \pi^2 M_2}{T_2^2}

M_2=M_1*(\frac{T_2}{T_1})^2

M_2=0.400*(\frac{0.52}{0.37}})^2

M_2=0.79kg

5 0
3 years ago
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