Question

I’m confused on this one

Answer 1

The surface area of a cylinder is the sum of the surface areas of the bases (2 circles) and the side of the cylinder (a rectangle).

The area of the bases is 2 times the area of each base, and each base is a circle,

The area of the side is a rectangle that has as length, the circumference of the base, and as width, the height of the cylinder.

$surface ~area = 2(\pi r^2) + (2 \pi r)h$

diameter = 2; radius = diameter/2 = 2/2 = 1

height = 16

$surface ~area = 2(\pi \times 1^2) + (2 \pi \times 1)\times 16$

$surface ~area = 2\pi + 2 \pi \times 16$

$surface ~area = 2\pi + 32 \pi$

$surface ~area = 34 \pi$

Answer 2

As we know surface area of a cylinder =2pi r sq
=>2*22/7*2*2
=>2*22/7*4
=>44*4/7
=>176/7
=>25.14 units sq (approx)...
Hope this helps u....