hola me pueden ayudar porfis aunque sea el punto 1 del el cuadro, solo necesito el cuadro porfa es que no entiendo, se los pido

the ramirez family comes home from vacation to find their mailbox overflowing with mail. there are 6 more magazines than there a

nirvana33 [79]

Answer:

9 magazines

Step-by-step explanation:

To solve this problem you will want to work backwards. Start with the junk mail. There is 18 junk mail and if there are 1/3 as many bills as junk mail then you will need to multiply 18 * 1/3. This equals 6 bills. If there is twice as many bills as letters then you will need to divide bills(6) by 2 which equals 3. If there are 6 more magazines than letters then you need to add 6 to the letters (3). 3 + 6 = 9

4 0

3 years ago

The manufacturer of an electronic device claims that the probability of the device failing during the warranty period is 0.005.

Zielflug [23.3K]

Answer:

The value is $P(X \ge 15) = 0.5$

Step-by-step explanation:

From the question we are told that

The probability of the device failing during the warranty period is $p = 0.005$

The sample size is $n = 3000$

The random variable considered is x = 15

Generally this is distribution is binomial given the fact that there is only two out comes hence

X which is a variable representing a randomly selected selected electronic follows a binomial distribution i.e

$X \~ \ B(n , p)$

Now the mean is mathematically evaluated as

$\mu = n * p$

=> $\mu = 3000 * 0.005$

=> $\mu =15$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np(1 -p )}$

=> $\sigma = \sqrt{3000 * 0.005 * (1 - 0.005 )}$

=> $\sigma = 3.86$

Now given that n is very large, then it mean that we can successfully apply normal approximation on this binomial distribution

So

$P(X \ge 15) = P( \frac{X - \mu}{\sigma } \ge \frac{x - \mu}{\sigma } )$

Now applying Continuity Correction we have

$P(X \ge (15-0.5)) = P( \frac{X - \mu}{\sigma } > \frac{(15 -0.5) - 15}{3.86 } )$

Generally $\frac{X - \mu}{\sigma } = Z (The \ standardized \ value \ of \ X)$

$P(X \ge (15-0.5)) = P(Z >-0.130 )$

From the z-table

$P(Z >-0.130 ) =0.5$

Thus

$P(X \ge 15) = 0.5$

7 0

3 years ago

4+2<-14 or – 5+98< 41

N76 [4]

Answer:

4+2<-14

6< -14 (False)

– 5+98< 41

93<41 (False)

Both statements are false.

6 0

3 years ago

What is the value of k in y = kx, if y = 12 when x = 24?

Brrunno [24]

Answer:

k = 0.5

Step-by-step explanation:

Substitue y = 12, x = 24 into y = kx.

12 = k × 24

24k = 12

k = 12 ÷ 24

k = 0.5 (final answer)

6 0

3 years ago

Read 2 more answers

It's always a good idea to check your solutions to any equation in the original equation. When solving an absolute value equatio

Andru [333]

You should must check for an extraneous solution when the variable appears both inside and outside the absolute value expression

<h3>What is an extraneous solution?</h3>

An extraneous solution is a solution that in obtained after completely solving an equation but it does not work in the original given equation.

You should must check for an extraneous solution when the variable appears both inside and outside the absolute value expression (Option D).

Learn more about extraneous solution: brainly.com/question/14054707

#SPJ1

7 0

2 years ago