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alukav5142 [94]
3 years ago
14

When Earth and the Moon are separated by a

Physics
2 answers:
Wewaii [24]3 years ago
6 0
     Using the Universal Gratitation Law, we have:

F= \frac{MmG}{d^2}  \\ MmG=2*10^{20}*(3.84*10^8)^2 \\ MmG=29.4912*10^36
 
     Again applying the formula in the new situation, comes:

F= \frac{MmG}{d^2} \\ F= \frac{29.4912*10^36}{(1.92*10^8)^2} \\ \boxed {F=8*10^{20}}

Number 4

If you notice any mistake in my english, please let me know, because i am not native.
faltersainse [42]3 years ago
6 0

The strength of the gravitational forces between two masses is
inversely proportional to the square of the distance between them.

So if you change the distance to

               (1.92 x 10⁸) / (3.84 x 10⁸)  =  1/2

of what it is now, then you would change the force to

                     1 / (1/2)²  =  4

of what it is now.

   (4) x (2 x 10²⁰)  =  8.0 x 10²⁰ newtons .

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Lilit [14]
C. Is the correct answer
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3 years ago
2. A car is moving south. It is getting faster. In which direction is the acceleration?
notka56 [123]
South it is the same direction the car is already moving
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3 years ago
Assume that the radius ????r of a sphere is expanding at a rate of 70 cm/min.70 cm/min. The volume of a sphere is ????=43???????
rodikova [14]

Answer:

the rate of change in volume with time is 280πr² cm³/min

Explanation:

Data provided in the question:

Radius of the sphere as 'r'

\frac{d\textup{r}}{\textup{dt}}  = 70 cm/min

Volume of the sphere, V = \frac{\textup{4}}{\textup{3}}\pi r^3

Surface area of the sphere as 4πr²

Now,

Rate of change in volume with time, \frac{d\textup{V}}{\textup{dt}}

 = \frac{d(\frac{\textup{4}}{\textup{3}}\pi r^3)}{dt}

= 3\times\frac{\textup{4}}{\textup{3}}\pi r^2}\times\frac{dr}{dt}

Substituting the value of \frac{dr}{dt}

= 3\times\frac{\textup{4}}{\textup{3}}\pi r^2}\times70

= 280πr² cm³/min

Hence, the rate of change in volume with time is 280πr² cm³/min

4 0
3 years ago
A child throws a ball with an initial speed of 8.00 m/s at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00
mr_godi [17]

Answer:

Explanation:

initial velocity, u = 8 m/s

vertical height, h = 1 m

θ = 40°

Let the horizontal distance is d and the time taken is t.

Use second equation of motion in vertical direction

h = ut + 1/2 at²

1 = 8 Sin 40 x t + 0.5 x 9.8 t²

1 = 5.14 t - 4.9t²

4.9t² - 5.14 t + 1 = 0

so, t = 0.26 s (smaller value)

So, the horizontal distance is

d = u cos 40 x t

d = 8 cos 40 x 0.26

d = 1.6 m

5 0
2 years ago
Help please I really need this​
My name is Ann [436]

Answer:

Explanation:

Height(h) = 4m; depth of the half filled tank 4m/2 =2m

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Density (d)=1000kg/m^3

Pressure = hdg

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Pressure = 19,600Pa

3 0
2 years ago
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