2 years ago

Topic: Chapter 19: Some wiggle room

Physics

1 answer:

Nana76 [90]2 years ago

3 0

Answer:

4.86 m

Explanation:

Given that,

The frequency produced by a humming bird, f = 70 Hz

The speed of sound, v = 340 m/s

We need to find how far does the sound travel between wing flaps. Let the distance is equal to its wavelength. So,

$v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{340}{70}\\\\\lambda=4.86\ m$

So, the sound travel 4.86 m between wings flaps.

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