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miv72 [106K]
3 years ago
5

I WILL WHOEVER ANSWER THIS QUESTION 40 POINTS AND WILL BE MARKED AS BRAINLIEST

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
7 0
A) It becomes sand
I know this because Minecraft
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Hybridization _____.
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The answer is number two here is an explanation of why I said number two ....

In chemistry, orbital hybridisation is the concept of mixing atomic orbitals into new hybrid orbitals suitable for the pairing of electrons to form chemical bonds in valence bond theory.
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Does a chemical bond join atoms together in a water molecule?
MrRissso [65]
Yes. 

A covalent bond holds it together, which is chemical. 
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How do scientists determine the number of neutrons in an isotope of an atom
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I think the answer would be

A. They find the number of protons
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3 years ago
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What is the composition, in atom percent, of an alloy that contains a) 44.5 lbm of silver, b) 84.7 lbm of gold, and c) 7.3 lbm o
Fed [463]

<u>Answer:</u> The atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

<u>Explanation:</u>

To convert the given masses into grams, we use the conversion factor:

1 lb = 453.6 grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ......(1)

To calculate the atom percent of substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Moles of substance}\times N_A}{\text{Total moles of sample}\times N_A}\times 100     ......(2)

where,

N_A = Avogadro's number

  • <u>Moles of Silver:</u>

Mass of silver = 44.5 lb = 20185.2 grams

We know that:

Molar mass of silver = 107.87 g/mol

Putting values in equation 1, we get:

\text{Moles of silver}=\frac{20185.2g}{107.87g/mol}=187.12mol

  • <u>Moles of Gold:</u>

Mass of gold = 84.7 lb = 38419.9 grams

We know that:

Molar mass of gold = 196.97 g/mol

Putting values in equation 1, we get:

\text{Moles of gold}=\frac{38419.9g}{196.97g/mol}=195.05mol

  • <u>Moles of Copper:</u>

Mass of copper = 7.3 lb = 3311.3 grams

We know that:

Molar mass of copper = 63.55 g/mol

Putting values in equation 1, we get:

\text{Moles of copper}=\frac{3311.3g}{63.55g/mol}=52.10mol

Total moles of the sample =

  • <u>For Silver:</u>

Moles of silver = 187.12 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of silver}=\frac{187.12\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of silver}=43.08\%

  • <u>For Gold:</u>

Moles of gold = 195.05 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of gold}=\frac{195.05\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of gold}=44.93\%

  • <u>For Copper:</u>

Moles of copper = 52.10 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of copper}=\frac{52.10\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of copper}=11.99\%

Hence, the atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

3 0
3 years ago
If a reaction has a very low activation energy, the products would be expected to form quickly at high temperatures. Select the
melamori03 [73]

Answer: Option (c) is the correct answer.

Explanation:

It is known that when Gibb's free energy, that is, \Delta G has a negative value then the reaction will be spontaneous and the formation of products is favored more rapidly.  

Activation energy is defined as the minimum amount of energy required to initiate a chemical reaction.

So, when reactants of a chemical reaction are unable to reach towards its activation energy then a catalyst is added to lower the activation energy barrier so the reaction can take place rapidly.

Since, the given reaction has low activation energy. Therefore, there is no need to add a catalyst.

And, when value of \Delta G is positive then the reaction is spontaneous in nature and formation of products is less favored.

Thus, we can conclude that for the given situation positive delta G is the reason that a reaction might form products very slowly, or not at all.

8 0
3 years ago
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