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3 years ago

When A is changing at a rate of -0.190 M⋅s−1 , how fast is B changing?

Chemistry

1 answer:

Tatiana [17]3 years ago

7 0

The rate of change of B is double that of A so:
rate of change of B = -2 x 0.19
rate of change of B = -0.38 M/s

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If percentage are given then we are taking total mass is 100 grams.So, the mass of each element is equal to the percentage given.

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Step 1 : convert given masses into moles.

Moles of Mg= $\frac {\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac {10.89g}{24g/mole}=0.45moles$

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Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

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