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mariarad [96]
3 years ago
7

Given that the antacid milk of magnesia contains 400. mg of Mg(OH)2 per teaspoon, calculate the number of milliliters of stomach

acid that are neutralized by 1 tablespoon of milk of magnesia. (1 tablespoon 3 teaspoons.) Express the volume in millilite rs to two significant figures.
Chemistry
1 answer:
dem82 [27]3 years ago
4 0

Answer:

1.5 ml

Explanation:

Assuming that the stomach acid is HCl then:

Mg(OH)₂ + 2HCl → MgCl₂ + H₂O

since

number of moles of Mg(OH)₂ = mass / molecular weight of Mg(OH)₂ = 3*400 mg / 58.3 gr/mol = 20.583 m mol

thus

number of moles of HCl required = number of moles of Mg(OH)₂*2 = 41.166 m mol  = 41.166 m moles

knowing that

density = mass / volume = (molecular weight* moles) / volume

volume =(molecular weight* moles)/ density

thus for HCl

volume =  (36.46 gr/mol * 41.166*10^-3 moles)/( 1 gr/cm³)= 1.5 cm³= 1.5 ml

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Bismuth-210 has a half life of 5.0 days if you had a sample of 60.00g of Bismuth-210 how much would be left after 15 days? (Show
Zielflug [23.3K]

Answer:

7.5 gm left

Explanation:

Bismuth-210 has a half life of 5 days

15 days is 15/5 = 3 half lives

since half the amount is left in 5 days or 1 half life

(1/2) x (1/2) x (1/2) the staring amount would be left in

3 half lives. so 1/8 is left

(1/8) x 60.0 = 7.5 gm left

5 0
3 years ago
How do H3O+ and OH relate to acids, bases and the pH scale?
Liula [17]

Answer: An acid is defined with having more [H₃O+] ions, and a base is defined with having more [OH-] ions. On the pH scale, an acid has a lower pH and a base has a higher pH. With this being said, the lower the pH, the more [H₃O+] ions are present and the higher the pH, the more [OH-] ions are present.

Explanation:

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6 0
2 years ago
8. Rewrite each of the following as an "ordinary” decimal
saveliy_v [14]

Answer:

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Explanation:

3 0
3 years ago
Write the Henderson-Hasselbalch equation for a propanoic acid solution ( CH3CH2CO2H , pKa=4.874 ) using the symbols HA and A− ,
zysi [14]

Answer:

a) [A⁻]/[HA] = 0.227

b) [A⁻]/[HA] = 0.991

c) [A⁻]/[HA] = 2.667

Explanation:

In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:

  • CH₃CH₂CO₂H = HA
  • CH₃CH₂CO₂⁻ = A⁻

pH = pka + Log [A⁻]/[HA]

pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H]

  • (a)

4.23 = 4.874 + Log [A⁻]/[HA]

-0.644 = Log [A⁻]/[HA]

10^{-0.644} = [A⁻]/[HA]

0.227 = [A⁻]/[HA]

  • (b)

4.87 = 4.874 + Log [A⁻]/[HA]

-0.004 = Log [A⁻]/[HA]

10^{-0.004} = [A⁻]/[HA]

0.991 = [A⁻]/[HA]

  • (c)

5.30 = 4.874 + Log [A⁻]/[HA]

0.426 = Log [A⁻]/[HA]

10^{0.426} = [A⁻]/[HA]

2.667 = [A⁻]/[HA]

6 0
4 years ago
A solid, pure substance containing just carbon and hydrogen is found to contain 35.8g of carbon and 3.72 g of hydrogen. how many
Igoryamba

Answer:

            4.36 g of Carbon

Solution:

Step 1: Calculate the %age of Carbon in given Solid as;

                        Mass of Carbon  =  35.8 g

                        Mass of Hydrogen  =  3.72

                        Total Mass  =  35.8 g + 3.72  =  39.52 g

                        %age of Carbon  =  (35.8 g ÷ 39.52 g) × 100

                        %age of carbon  =  90.58 %

Step 2: Calculate grams of Carbon in 4.82 g of given solid as;

                        Mass of Carbon  =  4.82 g × (90.58 ÷ 100)

                        Mass of Carbon  =  4.36 g

3 0
3 years ago
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