The equilibrium shift is if the HCl concentration is increased in the product.
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
<h3>What is the effect of concentration on equilibrium?</h3>
If the concentration of a substance is changed, then the equilibrium will shift in such a way that it minimizes the effect of change that occurs. If we increase the concentration of a reactant, then the equilibrium will shift to minimize the changes in the direction of the reaction which uses the reactants, so that the reactant concentration decreases.
<h3>Factors affecting the concentration of the reaction</h3>
- The temperature: As we increase the temperature, the average speed of the reactant molecules also increases. As many molecules move faster, a large number of molecules moving fast enough to react increases, making the faster formation of products.
- pressure
- and concentration of the system is the factors that affect equilibrium.
Thus, we concluded that with an increase in the concentration of reactant equilibrium shifts forward.
Learn more about equilibrium here:-
brainly.com/question/12252562
#SPJ4
Molarity=moles/litre
molarity=0.5/0.1
molarity=5.00m
Answer:
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Explanation:
From the given information:
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.
In this same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;
Rate factor in the absence of catalyst:

Rate factor in the presence of catalyst:

Assuming the catalyzed reaction and the uncatalyzed reaction are taking place at the same temperature :
Then;
the ratio of the rate factors can be expressed as:

![\dfrac{k_2}{k_1}={ \dfrac {e^{[ Ea_1 - Ea_2 ] }}{RT} }}](https://tex.z-dn.net/?f=%5Cdfrac%7Bk_2%7D%7Bk_1%7D%3D%7B%20%20%5Cdfrac%20%7Be%5E%7B%5B%20%20Ea_1%20-%20Ea_2%20%5D%20%7D%7D%7BRT%7D%20%7D%7D)
Thus;

Let say the assumed temperature = 25° C
= (25+ 273)K
= 298 K
Then ;



The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
ANSWERS:
Group 2 metal carbonates, nitrates and hydroxides decompose to heat to give the corresponding metal oxide and release CO2, NO2 and O2, and H2O respectively. The thermal stability increases down the group as theionic character of the compounds increases down the group.