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Fudgin [204]
3 years ago
8

Send Message

Chemistry
2 answers:
Schach [20]3 years ago
8 0

Answer:

OB) 1.0 atm

Explanation:

we have a mixture of hydrogen, nitrogen and methane and we have the following data

P_t= 3.0 atm

P_H=0.5atm\\P_{CH_4}=1.5 atm\\P_N=?

According to the law of Dalton the sum of the partial pressures of each gas is equal to the total pressure

Total pressure equation

P_t=P_H+P_{CH_4}+P_N

now we clear the partial pressure of nitrogen from the equation

P_t=P_H+P_{CH_4}+P_N\\P_t-P_H-P_{CH_4}=P_N\\3amt-0.5atm-1.5atm=P_N\\1atm=P_N

the partial pressure of nitrogen is 1 atm

the correct answer is OB) 1.0 atm

Ganezh [65]3 years ago
4 0

Answer:

1 Atm

Explanation:

Dalton's law

The total pressure is 3 Atm so all you have to do is subtract the other partial pressures from 3

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The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

6 0
3 years ago
What is h2o? I’m in 1st grade
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Answer:

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Explanation:

H20 means

H = Hydrogen

2 = 2 Hydrogen atoms

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Thanks!

Mark me brainliest!

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