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Anon25 [30]
3 years ago
14

DNA is always read mRNA is always read help !!!!!

Chemistry
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

genetic material

RNA becoz mRNA takes message of RNA

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What is veces??????????????????????????????????
tangare [24]
Veces is Spanish word for times.Hope I helped.
3 0
3 years ago
A gas occupies a volume of 31.0 ml at 19.0°C. If the gas temperature rises to 38.0°C at constant pressure. Calculate the new vol
Alik [6]

Answer:

The correct answer is 0.0033 L (33.0 mL)

Explanation:

We uses the Charles's law which describes the changes in the volume (V) of a gas and its temperature in Kelvin (T) at constant pressure. The mathematical expression is the following:

V₁/T₁ = V₂/T₂

We have the following data:

V₁= 31.0 mL = 0.0031 L

T₁= 19.0°C = 292 K

T₂= 38.0°C = 311 K

V₂= ?

We calculate V₂ from the mathematical expression, as follows:

V₂= V₁/T₁ x T₂ = 0.0031 L/(292 K) x 311 K = 0.0033 L

5 0
3 years ago
Of the groups below, which are the least chemically reactive?
seropon [69]

It is actually Group 3A elements. I just took the test.

8 0
3 years ago
At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)
sdas [7]

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

5 0
3 years ago
Us<br> What is the percent of O in<br> Cr2O3?<br> (Cr = 52.00 amu, O = 16.00 amu)<br> [? ]%
Gekata [30.6K]

The percent of O in  Cr₂O₃ : 31.58%

<h3>Further explanation</h3>

Given

Cr = 52.00 amu, O = 16.00 amu

Required

The percent of O

Solution

MW Cr₂O₃ = 2 x Ar Cr + 3 x Ar O

MW Cr₂O₃ = 2.52+3.16

MW Cr₂O₃ =152 amu

\tt \%O=\dfrac{3.Ar~O}{MW~Cr_2O_3}\times 100\%\\\\\%O=\dfrac{3.16}{152}\times 100\%\\\\\%O=31.58\%

8 0
3 years ago
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