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Bess [88]
2 years ago
8

10. The hottest stars in the sky are A about 200,000°c B about 5,800°c C about 22.000.

Chemistry
2 answers:
dimulka [17.4K]2 years ago
6 0

Answer:

The hottest known star, WR 102, is one such Wolf-Rayet, sporting a surface temperature more than 35 times hotter than the Sun.

<h3>Wolf-Rayet stars come in a variety of flavors.</h3>

<h3>So I'd say B about 5,800°c</h3>

<h3>Hope this helps, have an awesome day.</h3>
vredina [299]2 years ago
3 0

Answer: 22,000 C

Explanation:

Break the numbers apart to make them smaller then multiply and add them back to the big number and there is your answer

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2 years ago
Write the expression for the equilibrium constant Kp for the following reaction. (Enclose pressures in parentheses and do NOT wr
Liono4ka [1.6K]

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}

Where PPCl₃ is the partial pressure of PCl₃ (reactant), PCl₂ is the partial pressure of Cl₂ (reactant) and PPCl₅ is the partial pressure of PCl₅ (product).

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2 years ago
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4 0
3 years ago
Read 2 more answers
The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of
timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = 1.83g/cm^3=1.83g/ml

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml

Now we have to calculate the molarity of solution.

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0
3 years ago
What is the mass of the block of iron illustrated below?
Mandarinka [93]
VOLUME= 5cm*10cm*2cm =100cm^3
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7 0
3 years ago
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