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andre [41]
3 years ago
8

How to i factor this: 2/3x + 6

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
5 0
2/3x + 6.
Multiple your denominator on both sides (3•3 & 3•6)
Cross out the 3•3 & you now have 2x + 18
Now divide both sides by 2.
2x crosses out, leaving you with 18/2
x=9
adell [148]3 years ago
4 0
The answer would be:  2 (x/3 + 3) 
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​Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 640 randomly s
tatyana61 [14]

Answer:

Given:

Sample size, n = 640

Since result showed that 99.2​% of them would erase all of their personal information online if they could, we have:

P' = 99.2% = 0.992

Let's take p = 50%

Our null and alternative hypothesis will be :

H0 : u = 0.5

H1 : u > 0.5

In this case we are to check for the test statistic.

\frac{P' - p}{\sqrt{p(1-p)/n}}

= \frac{0.992 - 50}{\sqrt{50(1-50)/640}}

= 24.9

Test statistic, Z = 24.893

In conclusion, the results are significantly high, which suggets there is suffcient evidence to support the claim that most adults would erase all of their personal information online.

7 0
3 years ago
A commuter has $345 in his commuter savings account. This account changes by -$15 each week he buys a ticket. In one time period
Roman55 [17]

Answer:

A.16 weeks

B. $195

Step-by-step explanation:

A.

345-15x=345-240

345-15x=105

15x=240

x=16

B.

345-240=105

20x15=300

105+x=300

x=195

7 0
3 years ago
The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
Which situation is repesented by the graph
forsale [732]

Answer:

answer is A i think im not sure

Step-by-step explanation:

i dont know ask your teacher

4 0
3 years ago
Mr. franklin paid $33.20 for 8 gallons of gas. What is the price of 1 gallon ?
evablogger [386]
The price of 1 gallon is $4.15. You figure this out by dividing 33.20 by 8.
33.20/8 = 4.15
3 0
3 years ago
Read 2 more answers
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