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Montano1993 [528]
3 years ago
5

The period of a mechanical wave is 5 seconds. what is the frequency of the wave?

Physics
2 answers:
Natasha_Volkova [10]3 years ago
4 0
The frequency of a wave is just the reciprocal of the period.
For this one . . .

     Frequency  =  1/(period)  =  1/(5 sec)  =  0.2 per sec (0.2 Hz) .
blondinia [14]3 years ago
3 0

Answer:

Frequency of the wave is 0.2 Hz.

Explanation:

It is given that, the period of a mechanical wave is 5 seconds. We have to find the frequency of the wave. Time period of a wave is defined as the time taken by the wave to complete one cycle and the number of oscillations or vibrations in a medium is called the frequency of the wave.

The relationship between the time period and the frequency of the wave is given by :

f=\dfrac{1}{T}   T = time period

f=\dfrac{1}{5\ s}      

f = 0.2 Hertz

Hence, the correct option is (c) " 0.2 Hz ".                

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denis23 [38]

Answer: (a) t = 5.44 sec

(b) vf = 53.31 m/s

(c) s = 5.0m

Explanation: from the question, given data

the Height of the tower, h = 145m

from question

(a)

the initial velocity, v₁ = 0 m/s

s = v₁t + 1/2 gt²

-145 m = 0(t) + 1/2 (-9.8t²)

  t² = 145/4.9

   t² = 29.59

    t = 5.44 sec

(b)

the speed of the sphere at the bottom of the tower is

vf² = vi² +2as

vf² = 0 + 2(-9.8 × -145)

vf² = 2842

vf = 53.31 m/s

(c)

when caught, the sphere experiences a deceleration of;

   a = -29.0g

the time it would take to decelerate becomes;

vf = vi + at

0 = (53.31) + (-29 ×9.8)t

where t = 53.31 / 284.2

t = 0.1876 sec

∴ the distance travelled during the deceleration becomes;

vf² = vi² + 2as

s = (vf² - vi²) / 2a

s = (0 - 53.31²) / 2×-29×9.8

s = -2841.9561 / -568.4

s = 4.99 ≈ 5.0m

i hope this helps, cheers

4 0
3 years ago
What happens when bromine reacts with carbon?
serious [3.7K]
D. Electrons are shared between the bromine atoms and carbon atoms
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nadezda [96]

Answer:  Mass

Explanation:

8 0
3 years ago
A satellite circles the Earth in an orbit whose radius is twice the Earth’s radius. The Earth’s mass is 5.98 x 1024 kg, and its
gavmur [86]

Hello!

Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:

d = 2\pi r ← The circumference of the orbit

speed = orbital speed, we will solve for this later

time = period

Therefore:

T = \frac{2\pi r}{v}

Where 'r' is the orbital radius of the satellite.

First, let's solve for 'v' assuming a uniform orbit using the equation:
v = \sqrt{\frac{Gm}{r}}

G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)

m = mass of the earth (5.98 × 10²⁴ kg)

r = radius of orbit (1.276 × 10⁷ m)

Plug in the givens:
v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s

Now, we can solve for the period:

T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}

7 0
2 years ago
What happens if you go through a black hole ?
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Explanation:

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