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Montano1993 [528]
3 years ago
5

The period of a mechanical wave is 5 seconds. what is the frequency of the wave?

Physics
2 answers:
Natasha_Volkova [10]3 years ago
4 0
The frequency of a wave is just the reciprocal of the period.
For this one . . .

     Frequency  =  1/(period)  =  1/(5 sec)  =  0.2 per sec (0.2 Hz) .
blondinia [14]3 years ago
3 0

Answer:

Frequency of the wave is 0.2 Hz.

Explanation:

It is given that, the period of a mechanical wave is 5 seconds. We have to find the frequency of the wave. Time period of a wave is defined as the time taken by the wave to complete one cycle and the number of oscillations or vibrations in a medium is called the frequency of the wave.

The relationship between the time period and the frequency of the wave is given by :

f=\dfrac{1}{T}   T = time period

f=\dfrac{1}{5\ s}      

f = 0.2 Hertz

Hence, the correct option is (c) " 0.2 Hz ".                

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Soloha48 [4]

The momentum of the second ball was 15 kg.m/s.

<h3>What is inelastic collision?</h3>

In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.

In the given question,

Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.

Initial velocity of 1st ball of mass 3 kg is 1 m/s.

So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.

According to Principle of conservation of linear momentum for this inelastic collision,

Initial momentum of first ball + initial momentum of second ball =  final momentum of the system

⇒   initial momentum of second ball =   final momentum of the system - Initial momentum of first ball

= 18 kg.m/s - 3 kg.m/s.

= 15 kg.m/s.

Hence, initial momentum of second ball = 15 kg.m/s.

Learn more about momentum here:

brainly.com/question/24030570

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1 year ago
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Condensation, radiation, convection, conduction are many ways heat is transferred from atmosphere to ocean. however heat comes from the sun then, to the atmosphere.
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How long does it take to go blind looking at the sun?
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A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts
Viefleur [7K]

Answer:

4987N

Explanation:

Step 1:

Data obtained from the question include:

Mass (m) = 0.140 kg

Initial velocity (U) = 28.9 m/s

Time (t) = 1.85 ms = 1.85x10^-3s

Final velocity (V) = 37.0 m/s

Force (F) =?

Step 2:

Determination of the magnitude of the horizontal force applied. This can be obtained by applying the formula:

F = m(V + U) /t

F = 0.140(37+ 28.9) /1.85x10^-3

F = 9.226/1.85x10^-3

F = 4987N

Therefore, the magnitude of the horizontal force applied is 4987N

8 0
3 years ago
Measurements show that the enthalpy of a mixture of gaseous reactants decreases by during a certain chemical reaction, which is
snow_tiger [21]

The given question is incomplete. The complete question is as follows.

Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 338 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 187 kJ of work is done on the mixture during the reaction. Calculate the change in energy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. Is the reaction exothermic or endothermic ?

Explanation:

The given data is as follows.

    Change in enthalpy (\Delta H) = -338 kJ (as it is a decrease)

    Work done = 187 kJ,

    Change in energy (\Delta E) = ?

Now, according to the first law of thermodynamics the formula is as follows.

          \Delta H = \Delta E + P \Delta V

Hence, putting the given values into the above formula as follows.

        \Delta H = \Delta E + P \Delta V

Also, we know that W = P \Delta V

so,           \Delta H = \Delta E + W      

              -338 kJ = \Delta E + 187

              \Delta E = -151 kJ

Thus, we can conclude that the change in energy of the gas mixture during the reaction is -151 kJ.

5 0
3 years ago
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