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Marrrta [24]
3 years ago
14

Why are citizens obligated to respond to such documents?

Physics
1 answer:
Zina [86]3 years ago
5 0
To protect the constitutional right to confront ones accused
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A proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.
lawyer [7]

The change in potential energy of the proton is  5.6 x 10^{-17} Joule

<h3>What is a Uniform Electric Field ?</h3>

A uniform electric field is where the electric field strength is the same at all points in the field. In the uniform field, the force experienced by a charge is the same no matter where it is placed in the field.

Given that a proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.

  • The distance d = 10 cm = 0.1 m
  • Electric field E = 3.5 KN/C
  • Proton charge q = 1.6 x 10^{-19} C

The Work done = Fd

but F = Eq

Recall that Electric field E = F/q = V/d

Where V = potential difference.

Let us first calculate the V

E = V/d

V = Ed

Substitute all the parameters into the formula above

V = 3.5 × 10³ × 0.1

V = 350 v

from F/q = V/d

make F the subject of formula and substitute it in work formula

F = Vq/d

W.D = Vq/d x d

W.D = Vq

Substitute all the parameters into the formula above

W.D = 350 x 1.6 x 10^{-19}

W.D = 5.6 x 10^{-17} J

Work done = Energy = Potential Energy

Therefore, the change in potential energy of the proton is 5.6 x 10^{-17}<em> Joule</em>

<em />

Learn more about Electric Field here: brainly.com/question/14372859

#SPJ1

7 0
2 years ago
1. A stone of mass 0.8 kg is attached to a 0.9 m long string. The string will break if the tension exceeds 60 N. The stone is wh
melamori03 [73]

Answer:

1. A. 8.22. m/s

Explanation:

7 0
3 years ago
A research submarine has a 10-cm-diameter window that is 8.4 cm thick. The manufacturer says the window can withstand forces up
Dmitrij [34]
Pnet = Po + dgh 

<span>Density of saltwater = 1030 kg/m^3. </span>

<span>Disregard the thickness. Assuming it's a circular window, then the area is pi(r^2). </span>

<span>d = 20 cm = 0.2 m </span>
<span>r = d/2 = 0.1 m </span>

<span>A = pi(r^2) </span>
<span>A = 3.14159265(.1^2) </span>
<span>A = 0.0314159265 m^2 </span>

<span>p = F/A </span>
<span>p = (1.1 x 10^6) / (0.0314159265) </span>
<span>p = 35,014,087.5 Pa </span>

<span>1 atm = 101,325 Pa </span>

<span>P = Po + dgh </span>
<span>h = (P - Po) / dg </span>
<span>h = (35,014,087.5 - 101,325) / (1030 x 9.81) </span>
<span>h = 3 455.23812 m </span>
<span>h = 3.5 km</span>
8 0
3 years ago
Read 2 more answers
A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30° angle. The block’s initial speed is 10 m/s. What vert
Romashka [77]

Answer:

Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s

Explanation:

Given Data:

V is the overall velocity vector, Vi and Ui are its initial vertical and horizontal components

R = 10 m/s\\ Projection Angle (theta) = 30 degrees\\Vi   = 10*sin(30) = 5 m/s\\Ui  = 10*cos(30) = 8.66 m/s

To find:

Max Height h achieved

Calculation:

1) Using the 3^{rd} equation of motion, we know

2*a*s = Vf^{2}  - Vi^{2}

2) In terms of gravity g height h and  the vertical component of Velocity Vf , Vi.

3) As Vf = 0 as at maximum height the vertical component of velocity is zero maximum height achieved

2*g*h = Vf^{2}  -Vi^{2}

putting values

4) h = 0.784 m/s

5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)

3 0
3 years ago
Could I get help plz
Sloan [31]

Answer:

440hz

Explanation:

saxophone a plays at 430hz and a frequency of 5 beats per second can be heard so saxophone b is playing at a frequency 10hz louder than saxophone A making it 440hz

3 0
3 years ago
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