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ira [324]
3 years ago
14

A net force of 50 newtons is applied to a 20 kilogram cart that is already moving at 1 m/s the final speed of the cart was 3 m/s

for how long was the force applied need to show work please help me
Physics
1 answer:
valina [46]3 years ago
7 0

Answer:

0.8 seconds

Explanation:

F=ma

Let x be the seconds the force is applied.

m = 20kg

F = 50 Newtons (kg*m/sec^2)

acceleration, a, is provided for x seconds to increase the speed from 1 m/s to  3 m/s, an increase of 2m/s

Let's calculate the acceleration of the cart:

F=ma

(50 kg*m/s^2) = (20kg)*a

a = 2.5 m/s^2

---

The acceleration is 2.5 m/s^2.  The cart increases speed by 2.5 m/s every second.  

We want the number of seconds it takes to add 2.0 m/sec to the speed:

(2.5 m/s^2)*x = 2.0 m/s

x = (2.0/2.5) sec

x = 0.8 seconds

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4 years ago
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a rocket with a mass of 4kg accelerates up from the ground at a rate of 20ft m/s^2, what is the drag force acting on the rocket
Maru [420]

The drag force acting on the rocket is 80N.

<h3>Give an explanation of drag force?</h3>

The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.

The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.

The drag force acting on the rocket F = ma

Given,

m = 4kg, a = 20ftm/s²

Substituting m and a values in the above formula,

The drag force acting on the rocket F = 4×20

The drag force acting on the rocket F = 80N.

To know more about drag force visit:

brainly.com/question/15144984

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8 0
2 years ago
Based on the magnetic field lines shown what is the orientation of the mystery magnet ?
babunello [35]
I think it’s cannot be determined
4 0
3 years ago
A flare is dropped from an airplane flying horizontally at uniform velocity (constant speed in a straight line). Neglecting air
jolli1 [7]

Answer:

Option B (remain vertically under the plane) is the correct option.

Explanation:

  • A flare would follow a particle trajectory with horizontal direction somewhat like airplane velocity as well as initial maximum motion as null but instead, gravity will induce acceleration. It would be lowered vertically underneath the plane before flare had already sunk to something like the surface.
  • There is no different movement in the airplane nor even the flash. And none of them can change its horizontal level.  

Some other alternatives are given really aren't linked to the specified scenario. So choice B is the perfect solution to that.

7 0
3 years ago
A car is moving at a constant speed of 14 m/s when the driver presses down on the gas pedal and accelerates for 14 s with an acc
Vinil7 [7]

acceleration of car is 1.8 m/s^2

time = 14 s

initial speed = 14 m/s

so the final speed is calculated by

v_f = v_i + at

v_f = 14 + 14 * 1.8

v_f = 39.2 m/s

so the total distance moved in this interval of time is

d = \frac{v_f + v_i}{2}* t

d = \frac{39.2 + 14}{2}* 14

d = 372.4 m

now the average speed is given as

v = \frac{d}{t}

v = \frac{372.4}{14}

v = 26.6 m/s

so the average speed will be 26.6 m/s

7 0
3 years ago
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