The problem arose due to a difference in length. This was due to father not knowing the exact length of shoe used by the son. And this can be mitigated by the use of shoe fillers.
The length of an object implies how long the object is. And it is one of the fundamental unit of quantities measured in SI unit of meters.
Considering the given question, it can be observed that the father do not know the exact length of shoe that would fit the son appropriately. Thus the realized problem of the pair of shoes too long arose due to difference in length of the pair of shoes and the son's leg. This variation would not have occurred if the exact length of pair of shoes has been bought.
To mitigate this little problem, shoe fillers can be used.
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Answer:
the pressure will decrease by 1/2
Explanation:
PV=nRT
P=(nRT)/(V)
nRT are all constant so they will equal 1
V is 2
P=1/2
Answer:
Explanation:
Magnetic field B = 6 X 10⁻⁵ T.
Width of car = L (Let )
Velocity of car v = 100 km/h
= 27.78 m /s
induced emf across the body ( width ) of the car
= BLv
= 6 X 10⁻⁵ L X 27.78
166.68 X 10⁻⁵ L
Induced electric field across the width
= emf induced / L
E = 166.68 X 10⁻⁵ N/C
We suppose breadth of a typical car = 1.5 m
potential difference induced
= 166.68 x 1.5 x 10⁻⁵
250 x 10⁻⁵ V
= 2.5 milli volt.
The side of the car which is positively charged depends on the direction in which car is moving , whether it is moving towards the north or south.
Answer:
Find a recipient that you can put the object completely inside, and fill this recipient with water. After, you put the irregular solid you want to measure the volume inside, and the water will spill out the recipient. So you take the water that spilled out and uses a graduated recipient to measure the volume of water. The volume of the solid will be exactly the same volume of water that spilled of the first recipient
Power = (energy) / (time)
= (1370 joules) / (100 seconds)
= 13.7 joules/second
= 13.7 watts .
That's not an awful lot of power, especially for a strenuous activity like
rock-climbing. Shoot ! Even I could probably perform at that level.
Compare 13.7 watts to the light power coming out of a 20-watt night light.
13.7 watts = 0.018 horsepower. (rounded)