Current will be
now just pluf in the values and Voila..
Answer:
the electric field strength of this charge is two times the strength of the other charge
Explanation:
Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;
E1/E2 = Q2/Q1
E2 = E1 x Q1/Q2
= E x Q/ (Q/2)
= 2E
The lens equation gives d relation between focal length, object distance n image distance.
1/f = 1/v + 1/u
seldon
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