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viva [34]
3 years ago
10

What is the acceleration of a car that goes from 0 to 20m/s in 7 seconds?

Physics
1 answer:
nadezda [96]3 years ago
6 0

Answer:

2m/s^2

Explanation:

Clculate the acceleration:

V = u +at

20m/s = 0 + a*10s

a = 20m//10s

a = 2m/s²

From the data given , it is not possible to calculate the displacement , because no direction of motion is given

But it is possible to calculate the distance travelled

Distance = ut + ½ *a*t²

distance = 0 + ½ * 2m/s * 10²s

distance = 100m

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Some cities now implement signal lights designed to specifically apply to _____ rather than motorized vehicles.
dmitriy555 [2]

The correct answer is C; Bicycles.

Further Explanation:

In major cities, in the United States, have implemented signal lights specifically designed for bicycle riders. The riders also have their own designated bike lanes in many large cities. Drivers in vehicles, are to give the right of way to people on bicycles.

Bicycle riders are to follow the same laws and laws specifically for the riders or they can face fines and tickets.

Learn more about bicycle laws at brainly.com/question/8934107

#LearnwithBrainly

7 0
3 years ago
Please i need detailed explanation​
zubka84 [21]

Answer:

2Micro Farahds

Explanation:

Its in the picture.

I Hope it helps.

4 0
3 years ago
Increased force will increase acceleration true or false.
zalisa [80]
True. Force is acceleration therefor inverse force is increasing acceleration
8 0
3 years ago
Read 2 more answers
I need the answer for both of the questions please
Lady_Fox [76]
But even more pain on pain and then pain and pain ya feel me and even more pain okay and yes more pain
5 0
3 years ago
A spring is stretched from x=0 to x=d, where x=0 is the equilibrium position of the spring. It is then compressed from x=0 to x=
VARVARA [1.3K]

Answer:

The same amount of energy is required to either stretch or compress the spring.

Explanation:

The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

U=\frac{1}{2}k (\Delta x)^2

where

k is the spring constant

\Delta x is the stretch/compression of the spring

In the first case, the spring is stretched from x=0 to x=d, so

\Delta x = d-0=d

and the amount of energy required is

U=\frac{1}{2}k d^2

In the second case, the spring is compressed from x=0 to x=-d, so

\Delta x = -d -0 = -d

and the amount of energy required is

U=\frac{1}{2}k (-d)^2= \frac{1}{2}kd^2

so we see that the amount of energy required is the same.

7 0
4 years ago
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