The correct answer for this would be silicon dioxide.
Through heredity, I was able to gain the traits that I have today.
Hope this helped! Good luck! :)
We know, Weight = Mass * Gravity
Here, Mass = 20 Kg
Gravity = 10 m/s² [Approximate value ]
Substitute their values,
w = 20 * 10
w = 200 N
In short, Your Answer would be Option C
Hope this helps!
Answer:-
Electrocautery Device
Explanation:-
The heat and light produced like a discharge due to a low impedence connection is called arc flash. They can cause substantial damage including fire and injury.
Electrocauterization or electric surgery is the process of destroying tissue with electricity. In this process the electrode is held away from the tissue, so that when the air gap between the electrode and the tissue is ionized leading to an electric arc discharge.
Here a low impedence is used to since a return electrode burn will occur if the heat produced, over time, is not safely dissipated by the size or conductivity of the patient return electrode.
Hence an arc flash can result from a Electrocautery Device if proper precautions are not taken.
Answer:
2.30 liters.
Explanation:
- The balanced equation of the reaction is:
<em>Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,</em>
- It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂.
- The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: <em>PV = nRT</em>.
P is the pressure of the gas (P = 1.0 atm at STP),
V is the volume of the gas (V = 4.60 L),
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas (T = 273.0 K at STP).
∴ n = PV/RT = (1.0 atm)(4.6 L) / (0.082 L.atm/mol.K)(273.0 K) = 0.205 mol.
<u><em>Using cross multiplication:</em></u>
1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.
0.205 mole of CO₂ produces → ??? mole of O₂.
- The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole)(0.205 mole) / (1.0 mole) = 0.103 mole.
- ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol)(0.082 L.atm/mol.K)(273.0 K) / (1.0 atm) = 2.30 liters.