Answer:
1.169s
Explanation:
k = 0.851 M-1s-1
The unit of the rate constant, k tells us this is a second order reaction.
From the question;
Initial Concentration [A]o = 2.01M
Final Concentration [A] = One third of 2.10 = (1/3) * 2.10 = 0.67M
Time = ?
The integrated rate law for second order reactions is given as;
1 / [A] = (1 / [A]o) + kt
Making t subject of interest, we have;
kt = (1 / [A] ) - (1 / [A]o )
t = (1 / [A] ) - (1 / [A]o ) / k
Inserting the values;
t = [ (1 / 0.67 ) - (1 / 2.10) ] / 0.851
t = ( 1.4925 - 0.4975 ) / 0.851
t = 0.995 / 0.851
t = 1.169s
[A] = 0.13073 M ≈ 0.13 M ( 2 s.f)
Answer:
False
Explanation:
Chemical reaction equation:
C₅H₁₂ + 8O₂ → 2CO₂ + 6H₂O
Most chemical reactions obey the law of conservation of mass. By so doing, the number of chemical elements on both sides of the expression must be balanced.
Reactants Products
C 5 4
H 12 12
O 16 10
We see that for C and O, the number of atoms on both sides of the expression differs and so, it is not balanced.
Answer:
Matching the reaction on the top with the corresponding reaction on the left:
Explanation:
A) 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)
is Electrolysis breaks down water to form hydrogen and oxygen gas
B) 2H2(g) + O2(g) = 2H2O(g)
is
A bright light is produced when magnesium reacts with the oxygen in air to form magnesium oxide
Answer:
38.7%
41.3%
20%
Explanation:
The percentage composition helps to know the what percent of the total mass of a compound is made up of each of the constituent elements or groups.
To solve this problem:
- find the formula mass by adding the atomic masses of the atoms that makes up the compound.
- place the mass contribution of the element or group to the formula mas and multiply by 100;
Compound:
Ca₃(PO₄)₂
Formula mass = 3(40) + 2[31 + 4(16)]
= 120 + 2(95)
= 120 + 190
= 310
%C =
x 100 = 38.7%
%P =
x 100 = 41.3%
%O =
x 200 = 20%
Answer: ![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.
The given balanced equilibrium reaction is:

The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)
Thus the equilibrium constant expression for this reaction is ![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)