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mart [117]
3 years ago
15

What conclusion can be drawn about the relationship between the arrangement of elements on the periodic table and the patterns o

bserved in their properties ?
1 ) - properties of elements are related to atomic numbers.
2 )- properties of elements are related to ductility.
3 )- properties of elements are related to malleability.
4 )- properties of elements are related to luster.
Chemistry
2 answers:
siniylev [52]3 years ago
6 0
The answer is <span>properties of elements are related to atomic numbers.</span>
Lelechka [254]3 years ago
5 0
Im pretty sure the answer would be number one.
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Answer:

Mn = 43,783

Mw = 60,000

Mz = 73,333

narrow distribution = 1.37

Explanation:

The molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000. This means their Mi is respectively: (The molar weight (Mi) of the fractions)

Fraction 1 : Mi = 20  *10^3

Fraction 2: Mi = 40 *10^3

Fraction 3 : Mi = 60 *10^3

Fraction 4: Mi = 80 *10^3

Fraction 5 : Mi = 100  *10^3

The ΣMi = 300*10^-3

The Wi (mass of the fractions is for all the fractions the same, let's say 1)

So Wi = 1+1+1+1+1 = 5

Since number of moles = mass / Molar mass

The number of moles is respectively: ni = Wi/Mi (x10^5)

Fraction 1 : ni = Wi/Mi = 1/20000 = 5

Fraction 2: ni = 1/40000 = 2.5

Fraction 3 : ni =1/60000 = 1.67

Fraction 4: ni = 1/80000 = 1.25

Fraction 5 : ni= 1/100000 = 1

The Σni = 11.42

Mn = ΣWi/ni = 5/11.42*10^-5 = 43,783

Mw = (ΣWi * Mi)/ΣWi  = 300,000 /5 = 60,000

Mz = (ΣWi * Mi²)/ΣWi *Mi = (4*10^8 +16*10^8 +36*10^8 +64*10^8 +100*10^8) /300,000  =73,333

Mz/Mn = narrow distribution =60,000/43,783 = 1.37

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Explanation:

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<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.

<u>Explanation:</u>

The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

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C=I\times t

where,

C = charge

I = current = 0.490 A

t = time required (in seconds) = 50\times 60=300s    (Conversion factor: 1 min = 60 s)

Putting values in above equation, we get:

C=0.490\times 300=147C

  • To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

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F = Faradays constant = 96500

\text{Moles of electrons}=\frac{147}{96500}=1.52\times 10^{-3}mol

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\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

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n = number of electrons transferred = 3

Putting values in above equation, we get:

\text{Moles of Gallium}=\frac{1.52\times 10^{-3}}{3}=5.077\times 10^{-4}mol

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Gallium = 5.077\times 10^{-4}mol

Molar mass of Gallium = 69.72 g/mol

Putting values in above equation, we get:

5.077\times 10^{-4}mol=\frac{\text{Mass of Gallium}}{69.72g/mol}\\\\\text{Mass of Gallium}=0.0354g

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.

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