4C₃H₅(NO₃)₃
------> 12CO₂
+ 6N₂
+ 10H₂O
+ O₂![_{(g)}](https://tex.z-dn.net/?f=_%7B%28g%29%7D%20)
mol of CO₂ = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D%20)
= ![\frac{25g}{44.01 g/mol}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25g%7D%7B44.01%20g%2Fmol%7D%20)
mol ratio of CO₂ : C₃H₅(NO₃)₃
12 : 4
∴ if mole of CO₂ = 0.568 mol
then " " C₃H₅(NO₃)₃ = ![\frac{0.568 mol}{12} * 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B0.568%20mol%7D%7B12%7D%20%20%2A%20%204)
= 0.189 mol
∴ mass of nitroglycerin = mole * Mr
= 0.189 mol * 227.0995 g / mol
= 43.00 g
That would be anaerobic fermentation
I hope I've helped!
Answer:
0.00420
Explanation:
The equation is Q=mc(T(final)-T(initial), where c is the specific heat, Q is heat supplied, m is mass, T(final) is final temperature and T(initial) is initial temperature (you'll see this written as delta T, which means change in temperature).
2520 = Q
m = 10.0kg; answer choices are in g, not kg, so multiply by 1000 to get m in g; m = 10000 g
Plug in the values you have and solve for c.
2520=(10000)(c)(70-10)
2520=600000c
c=0.0042 j/(gc)
1. A star
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5. A light year