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ivolga24 [154]
3 years ago
12

If I could lift up to ten tons and I threw a ball the size of an orange but weighed a ton, to the ground, how big of an impact w

ould it make? And could you also show me the equation to solve similar problems myself. Thank you.
Physics
1 answer:
Anarel [89]3 years ago
5 0

Answer:

The impact force is 98000 N.

Explanation:

mass = 10 tons

The impact force is the weight of the object.

Weight =mass x gravity

W = 10 x 1000 x 9.8

W = 98000 N

The impact force is 98000 N.

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Which of the following distinguishes the isotope uranium-238 from the isotope uranium-235?
WITCHER [35]

Answer: A

Explanation:

Isotopes of different elements differ by the number of neutrons inside the nucleus.

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2 years ago
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Elza [17]

1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum

7 0
3 years ago
An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
sineoko [7]

Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

Open tube:

f=\frac{v_s}{2L}         (1)

vs: speed of sound = 343m/s

L: length of the open tube = 0.47328m

You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

Closed tube:

f'=\frac{v_s}{4L'}

L': length of the closed tube = 0.702821m

f'=\frac{343m/s}{4(0.702821m)}=122.00Hz

Next, you use the following formula for the beat frequency:

f_b=|f-f'|=|362.36Hz-122.00Hz|=240.35Hz

The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz

7 0
3 years ago
On your first trip to Planet X you happen to take along a 280 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r
arsen [322]

Answer:

5.31143691523 m/s²

Explanation:

m = Mass = 280 g

x = Displacement of spring = 21.7 cm

Time period

T=\dfrac{14}{11}\\\Rightarrow T=1.27\ s

Angular velocity is given by

\omega=\dfrac{2\pi}{T}\\\Rightarrow \omega=\dfrac{2\pi}{1.27}\\\Rightarrow \omega=4.94739\ rad/s

\omega=\sqrt{\dfrac{k}{m}}\\\Rightarrow k=\omega^2m\\\Rightarrow k=4.94739^2\times 0.28\\\Rightarrow k=6.85346698739\ N/m

From Hooke's law

mg=kx\\\Rightarrow g=\dfrac{kx}{m}\\\Rightarrow g=\dfrac{6.85346698739\times 0.217}{0.28}\\\Rightarrow g=5.31143691523\ m/s^2

The acceleration due to gravity on the planet is 5.31143691523 m/s²

Yes, I have been able to satisfy my curiosity.

7 0
3 years ago
Black widow (m=57000 g) shovels snow, holding the shovel at a 40 degree angle above the ground. If she uses a constant force of
Dima020 [189]

Answer:

She does a work of 689.44 J in the snow.

Explanation:

A force is said to do work when it alters the state of motion of a body. The work of the force on that body will be equivalent to the energy needed to move it.

In other words, Work is a form of energy transmission between bodies. In order to carry out work, a force must be exerted on a body and it must move.

The work is equal to the product of the force times the distance and the cosine of the angle that exists between the direction of the force and the direction that the moving point or object travels:

W= F*d* cos Ф

Work W is measured in joules (J), force is measured in newtons (N), and displacement in meters (m).

In this case:

  • F= 180 N
  • d=5 m
  • Ф= 40 degrees

Replacing:

W= 180 N*5 m* cos 40

Solving:

W= 689.44 J

<u><em>She does a work of 689.44 J in the snow.</em></u>

7 0
3 years ago
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