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AleksandrR [38]
3 years ago
7

Water on the kitchen floor at home is considered a safety hazard.

Physics
2 answers:
svp [43]3 years ago
6 0
Yes it is, cause someone could slip and accidentally stab themselves
Slav-nsk [51]3 years ago
4 0
No, because on the hard wood, it is usually sort of grippy so you would not slip, and on carpet the carpet absorbs the water so it is inside and around the carpet not visible.
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What evidence can you cite to support the claim that the frequency of light does not change upon reflection?
sergiy2304 [10]

Answer: The color of an image is identical to the color of the object forming the image. When you look at yourself in a mirror, the color of your eyes doesn’t change. The fact that the color is the same is evidence that the frequency of light doesn’t change upon reflection. 2.

Hope this helps!!

5 0
3 years ago
How to use kinetic energy to calculate velocity
BartSMP [9]

As we know the formula of kinetic energy is

KE = \frac{1}{2} mv^2

here given that

KE = 150,000 J

mass = 120 kg

we can use this to find speed

150,000 = \frac{1}{2} * 120 * v^2

v^2 = 2500

v = 50 m/s

So speed of above object is 50 m/s

7 0
3 years ago
What is the formula for silver nitrate
serious [3.7K]

Answer:

Explanation:

Agno3

8 0
3 years ago
A transverse wave on a string is described by the wave function
svp [43]

The period of the transverse wave from what we have here is 0.5

<h3>How to find the period of the transverse wave</h3>

The period of a wave can be defined as the time that it would take for the wave to complete one complete vibrational cycle.

The formula with which to get the period is

w = 4π

where w = 4 x 22/7

2π/T = 4π

6.2857/T = 12.57

From here we would have to cross multiply

6.2857 = 12.57T

divide through by 12.57

6.2857/12.57 = T

0.500 = T

Hence we can conclude that the value of T that can determine the period based on the question is 0.500.

Read more on transverse wave here

brainly.com/question/2516098

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5 0
1 year ago
A planet orbits a star, in a year of length 3.37 x 107 s, in a nearly circular orbit of radius 1.04 x 1011 m. With respect to th
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Answer

Given,

Time period of star,T = 3.37 x 10⁷ s

Radius of circular orbit,R = 1.04 x 10¹¹ m

a) Angular speed of the planet

   \omega = \dfrac{2\pi}{T}=\dfrac{2\pi}{3.37\times 10^{7}}

   \omega = 1.864\times 10^{-7}\ rad/s

b) tangential speed

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       v = 1.94 x 10⁴ m/s

c) centripetal acceleration magnitude

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          a = 3.62 x 10⁻³ m/s²

8 0
3 years ago
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