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Soloha48 [4]
3 years ago
8

Explain how waves, energy, and matter are related

Physics
1 answer:
Stels [109]3 years ago
3 0

Answer:

Mechanical waves need matter to transfer energy while electromagnetic waves do not. ... Waves change direction when they move from one material into another (matter) through the process of refraction. The wave will change direction when the speed of the wave changes.

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NASA is designing a mission to explore Titan, the largest moon of Saturn. Titan has numerous hydrocarbon lakes containing a mix
Vitek1552 [10]

Answer:

Total pressure in atmosphere  IS 4.36 atm

Explanation:

Given Data:

Depth of lake is 400 mtr

surface tension is 147 kilopascals

surface temperature  94 kelvin

Gravity = 1.35 m/s^2

specific gravity of methane(liquid) = 0.415

specific gravity of ethane(liquid) = 0.546

density of methane can be obtained as

\rho_{methane} = 0.415\times 1000 = 415 kg/m^3

Density of ethane can be obtained as

\rho_{ethane} = 0.546\times 1000 = 546 kg/m^3

Total pressure in atmosphere can be obtained as

P = surface\ tension + \rho_{max}gh

 = 147 +546\times 1.35\times 400\times 10^{-3}

  = 441.84 kPa

= 441.84\times 0.009869 atm\kPa

 = 4.36 atm

7 0
3 years ago
Which is the fundamentals law of energy?<br><br>​
Bingel [31]

" <em>Energy is never created or destroyed.</em> "

All the rest is commentary.

7 0
3 years ago
Read 2 more answers
Rubber is a type of _________.<br> radiator<br> distributor<br> insulator<br> conductor
Talja [164]
C. insulator
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5 0
3 years ago
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HELP ASAP <br> Describe when contact metamorphism occurs?
diamong [38]

Contact metamorphism occurs adjacent to igneous intrusions and results from high temperatures associated with the igneous intrusion. Since only a small area surrounding the intrusion is heated by the magma, metamorphism is restricted to the zone surrounding the intrusion, called a metamorphic or contact aureole

5 0
3 years ago
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A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
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